Answer:
Option (c) Acceleration is 1/2x the original acceleration
Explanation:
To know the the correct answer to the question, we shall determine the acceleration of the box in each case.
Case 1:
Mass (m) = m
Force (F) = 20 N
Acceleration 1 (a₁) =?
F = ma₁
20 = m × a₁
Divide both side by m
a₁ = 20 / m
Case 2:
Mass (m) = 2m
Force (F) = 20 N
Acceleration 2 (a₂) =?
F = ma₂
20 = 2m × a₂
Divide both side by 2m
a₂ = 20 / 2m
a₂ = 10 / m
Finally, we shall determine the acceleration of the box after the mass was doubled. This can be obtained as illustrated below:
Acceleration 1 (a₁) = 20 / m
Acceleration 2 (a₂) = 10 / m
a₂ : a₁ = 10 / m : 20 / m
a₂ / a₁ = 10 / m ÷ 20 / m
a₂ / a₁ = (10 / m) × (m / 20)
a₂ / a₁ = ½
Cross multiply
a₂ = ½a₁
Thus, the acceleration of the box after the mass was doubled is ½ times the original acceleration.
<h3><u>Answer;</u></h3>
Dilute solution
One gram of salt in 100 liters of water could be considered a <em><u>dilute solution</u></em>.
<h3><u>Explanation</u>;</h3>
- <em><u>A solution is a mixture that is composed of two or more substances. It is formed when one substance (solute) dissolves on another called solvent. </u></em>
- Solutions are homogeneous mixtures as the substances in it are always in the same phase. <em><u>A solution may be concentrated or dilute depending on the amount of solute or solvent in the solution.</u></em>
- <u>A dilute solution has more solvent that solute while a concentrated solution has more solute than the solvent. In this case, </u><em><u>a solution containing 1 g of slat which is the solute in a 100 liters of water is an example of dilute solution.</u></em>
the missing force is spring force.
The object is hanging from the spring and the spring is stretched by some distance from its equilibrium position. due to this stretch in the spring , a spring force starts acting on the object trying to regain its equilibrium position.
the spring force is given as
F = kx
where F = spring force ,k = spring constant , x = stretch in the spring.
the spring force balances the weight of the object in down direction and hence keeps the block from falling down.
Answer:
If we consider a system where the y-axis as the South-North line, and the x-axis as the West-East line (where North and East are the positive sides)
We know that the sun goes from East to West, so in our system, the sun goes from the positive side of the x-axis to the negative side of the x-axis.
Where we would see this if we were standing right in the equator line.
If we where in other point of the planet, the Sun will stil move from East to West, but it will have a little tilt along the path, so we will have a little displacement in the y-axis. This displacement will depend on where we are, if we are at the North of the equator, we will se that the sun seems to go a little towards South as it goes to the West side.
We use the formula,
Here, h is the variable represents the height of the flare in feet when it returns to the sea so, h = 0 and u is the initial velocity of the flare, in feet per second and its value of 192 ft/sec.
Substituting these values in above equation, we get
.
Here, t= 0 neglect because it is the time when the flare is launched.
Thus, flare return to the sea in 12 s.
