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Ymorist [56]
3 years ago
14

Which of the following is a monomial?

Mathematics
1 answer:
UkoKoshka [18]3 years ago
5 0

Answer:

It is D. ,C B

Step-by-step explanation:

Mono means single/one but binomial is only first because binomial is only (... +...)

So monomials are B,C,D

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You need 3 sticks of butter for every 24 cookies you bake. How many sticks of butter for 5 cookies
tigry1 [53]

Answer:

5:40

Step-by-step explanation:

24 / 3 = 8

x / 5 = 8

x = 5 * 8

x = 40

5 0
2 years ago
Read 2 more answers
Please answer these question I will mark brainliest please only do part c and f​
gavmur [86]

Answer:

c.15+2z/6x-12y

f.7a+b/4a-6b

Step-by-step explanation:

z+1/x-2y - 2x-3/2x-4y + z/3x-6y

z+1/x-2y - 2x-3/2(x-2y) + z/3(x-2y)

6(z+1)-3(2z-3)+2z

15+2z/6x-12y

3a/2a-3b - a+b/2(-3b+2a)

6a+a+b/2(2a-3b)

7a+b/4a-6b

8 0
3 years ago
2x - 2y = -8<br> x + 2y = -1<br> (-3,1)<br> O<br> (-14, 1)<br> (0,4)<br> (1,5)
trasher [3.6K]

Answer:

2x - 2y = -8

x + 2y = -1

3x = -9

x = -3

-3 + 2y = -1

2y = 2

y = 1

(-3, 1) is the solution

Step-by-step explanation:

6 0
2 years ago
Hai came someone help I too lazy to do it...
baherus [9]

Answer: 4 Cups

I think in order to solve this, you would need to add up the fractions that they used. So it would be,

\frac{1}{4}+\frac{1}{4}+\frac{3}{8}+\frac{3}{8}+\frac{5}{8}+\frac{5}{8}+\frac{5}{8}+\frac{7}{8}   Transform the Expressions

\frac{1+1}{4} +\frac{3+3+5+5+5+7}{8}    Calculate the sum

\frac{2}{4} +\frac{28}{8}    Reduce

\frac{1}{2}+\frac{7}{2}   Transform the Expression

\frac{1+7}{2}   Calculate

\frac{8}{2}  Reduce the Fraction

4

Please mark brainliest if this helped you :)

3 0
2 years ago
Plisss help on my assesment
Anon25 [30]

Answer:

The first one is equivalent [the 6x+48 = 2(3x+24)] and the second one is <u>NOT</u> equivalent [the 7x+21 ≠ 2(5x+3)]

Step-by-step explanation:

Just follow distributive property to solve these. You can ignore the first expression in both until you have to compare the answers.

1. 6x+48 and 2(3x+24)

2(3x+24) ---> 2(3x) + 2(24) ---> <u>6x + 48</u>

Bring in the first expression ~ <u>6x+48 and 6x+48 </u>

They are the same, so they are equivalent

2. 7x+21 and 2(5x+3)

2(5x+3) ---> 2(5x) + 2(3) ----> 10x + 6

Bring in the first expression ~ <u>7x+21 and 10x + 6</u>

They are NOT the same, so they are NOT equivalent

6 0
3 years ago
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