Question

Compound A reacts with Compound B to form only one product, Compound C, and it's known the usual percent yield of C in this reaction is 78%. Suppose 10.0 g of A are reacted with excess Compound B, and 12.9g of Compound C are successfully isolated at the end of the reaction.
1. What was the theoretical yield of C?
2. How much B was consumed by the reaction?

Answer 1

Answer:

1. 16.54 grams.

2. 6.64 grams.

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$A+B\rightarrow C$

Thus, with the given information, the theoretical yield of C is:

$m_C^{theoretical}=\frac{12.9g}{0.78}=16.54g$

Moreover, by considering the law of conservation of mass, the mass at the beginning of the reaction equals the mass at the end of the reaction, therefore, the mass of B that was consumed was:

$m_B=m_C-m_A=16.54g-10.0g=6.64g$

Best regards.