Answer:
44,901 kilo Joule heat is released when
grams of ammonia is produced.
Explanation:
Moles of ammonia gas produced :

According to reaction, when 2 moles of ammonia are produced 9.18 kilo joules of energy is also released.
So, When 978.235 moles of ammonia gas is produced the energy released will be:

(negative sign indicates that energy is released as heat)
44,901 kilo Joule heat is released when
grams of ammonia is produced.
Answer:
The salt and sugar as well as the baby power and granulated sugar are the independent variables.
The dependent variable is how it reacts (will it dissolve or not)
Explanation:
Answer: 9.08 L
Explanation:
To calculate the moles :

According to stoichiometry :
4 moles of
require = 3 moles of 
Thus 0.54 moles of
will require=
of 
Standard condition of temperature (STP) is 273 K and atmospheric pressure is 1 atm respectively.
According to the ideal gas equation:

P = Pressure of the gas = 1 atm
V= Volume of the gas = ?
T= Temperature of the gas = 273 K
R= Gas constant = 0.0821 atmL/K mol
n= moles of gas= 0.405

Thus 9.08 L of
at STP would be required
Heat
gained or loss in a system can be calculated by multiplying the given mass to the
specific heat capacity of the substance and the temperature difference. It is
expressed as follows:<span>
Heat = mC(T2-T1)
When two objects are in contact,
it should be that the heat lost is equal to what is gained by the other. So, the heat released by the lead is equal to the heat that is absorbed by the water.
</span>Heat = mC(T2-T1) = 50.0 mL (1.00 g/mL) (4.18 J/g °C) (20 °C - 18 °C) = 418 J<span>
</span>