Answer:
The correct order of the elements, taking into account their ionic radius from highest to lowest, is:
<em>a) Cl⁻¹ > F⁻¹ > Na⁺¹ > Mg⁺²</em>
<em>b) S⁻² > O⁻² > Li⁺¹ > Be⁺²</em>
<em>c) S⁻² > Cl⁻¹ > K⁺¹ > Na⁺¹</em>
Explanation:
In ions the ionic radius is determined by the amount of electrons an element gains or loses to become an ion. The more negative an ion is, the greater its ionic radius.
As a rule, anions (negative charge) have a larger ionic radius than cations (positive charge), because the loss of electrons means a contraction of the ionic radius, while the gain of electrons means a greater radius.
To determine which ionic radius is greater in anions or cations with the same charge, it must be considered that in the periodic table the ionic radius increases from top to bottom and from right to left.
Learn more:
Ionic radius example brainly.com/question/2279609
Answer:
pH = 4.8
Explanation:
A buffer is formed by a weak acid (0.145 M HC₂H₃O₂) and its conjugate base (0.202 M C₂H₃O₂⁻ coming from 0.202 M KC₂H₃O₂). The pH of a buffer system can be calculated using Henderson-Hasselbalch's equation.
![pH = pKa + log\frac{[base]}{[acid]} \\pH = -log(1.8 \times 10^{-5} )+log(\frac{0.202M}{0.145M} )\\pH=4.8](https://tex.z-dn.net/?f=pH%20%3D%20pKa%20%2B%20log%5Cfrac%7B%5Bbase%5D%7D%7B%5Bacid%5D%7D%20%5C%5CpH%20%3D%20-log%281.8%20%5Ctimes%2010%5E%7B-5%7D%20%29%2Blog%28%5Cfrac%7B0.202M%7D%7B0.145M%7D%20%29%5C%5CpH%3D4.8)
Answer:
P.E = 25.48 J
Explanation:
Given data:
Mass = 2 Kg
Height = 1.3 m
Potential energy = ?
Solution:
Formula:
P.E = m . g . h
P. E = potential energy
m = mass in kilogram
g = acceleration due to gravity
h = height
Now we will put the values in formula.
P.E = m . g . h
P.E = 2 Kg . 9.8 m /s² . 1.3 m
P.E = 25.48 Kg. m² / s²
Kg. m² / s² = J
P.E = 25.48 J
When q is the heat energy in joules (J)
so, according to this formula, we can get q (in joule unit):
q = M*C*ΔT
when M is the mass of the water sample = 1.85 g
C is the specific heat capacity of water = 4.18 J/g.°C
and Δ T is the difference in temperature (Tf-Ti) = 33 - 22 = 11°C
So, by substitution, we will get the value of q ( in Joule):
∴ q = 1.85 g * 4.18 J/g.°C * 11 °C
= 85 J
