The oxidation number sulfur in H₂S is -2.
A compound's total number of oxidations must be zero.
The two hydrogen atoms in the chemical hydrogen sulfide, H₂S, each have an oxidation number of +1, making a total of +2. As a result, the compound's sulfur has an oxidation number of -2, and the total number of oxidations is 0.
Assume that the sulfur atom in H₂S has an oxidation number of x.
S be x.
Now,
2+x=0
⇒x=−2
<h3>What is oxidation number?</h3>
The total number of electrons that an atom either receives or loses in order to create a chemical connection with another atom is known as the oxidation number, also known as the oxidation state.
Depending on whether we are taking into account the electronegativity of the atoms or not, these phrases can occasionally have a distinct meaning. Coordination chemistry commonly makes use of the phrase "oxidation number."
<h3>What distinguishes an oxidation number from an oxidation state?</h3>
In contrast to the oxidation state, which indicates how oxidised an atom is in a molecule, the oxidation number describes the charge that the core metal atom will retain once all ligands have been removed.
To know more about oxidation number:
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Answer: plate
Explanation: Plates grinding past each other in opposite directions create faults called transform faults. Powerful earthquakes often strike along these boundaries. The San Andreas Fault is a transform plate boundary that separates the North American Plate from the Pacific Plate.
Answer:
each of the above (A, B, and C) occurs
Explanation:
When an ionic compound dissolves in the water, the following happens :
-- the solvent solute attractive forces tries to overcome the solute solute attractions.
-- the water dipoles' negative end attracts the positive ions
-- the water dipoles' positive end attracts the negative ions
For example,
NaCl which is an ionic compound and also a strong electrolyte, it dissociates into water on the hydrated Na cations as well as Cl anions.
In water, the oxygen has negative charge and thus attracts the positive ions of the sodium, whereas the hydrogen is of positive and it attract the ions of chlorine which is negative.
Answer:
Sofia the firstttdbshsgshaksus
Complete Question
The rate of a certain reaction is given by the following rate law:
![rate = k [H_2][I_2]](https://tex.z-dn.net/?f=rate%20%3D%20%20k%20%5BH_2%5D%5BI_2%5D)
rate Use this information to answer the questions below.
What is the reaction order in 
?
What is the reaction order in 
?
What is overall reaction order?
At a certain concentration of H2 and I2, the initial rate of reaction is 2.0 x 104 M / s. What would the initial rate of the reaction be if the concentration of H2 were doubled? Round your answer to significant digits. The rate of the reaction is measured to be 52.0 M / s when [H2] = 1.8 M and [I2] = 0.82 M. Calculate the value of the rate constant. Round your answer to significant digits.
Answer:
The reaction order in is n = 1
The reaction order in is m = 1
The overall reaction order z = 2
When the hydrogen is double the the initial rate is 
The rate constant is 
Explanation:
From the question we are told that
The rate law is
The rate of reaction is 
Let the reaction order for be n and for be m
From the given rate law the concentration of is raised to the power of 1 and this is same with so their reaction order is n=m=1
The overall reaction order is
At
![2.0*10^{4} = k [H_2] [I_2] ---(1)](https://tex.z-dn.net/?f=2.0%2A10%5E%7B4%7D%20%20%3D%20k%20%20%5BH_2%5D%20%5BI_2%5D%20---%281%29)
= > ![k = \frac{2.0*10^{4}}{[H_2] [I_2] }](https://tex.z-dn.net/?f=k%20%20%3D%20%5Cfrac%7B2.0%2A10%5E%7B4%7D%7D%7B%5BH_2%5D%20%5BI_2%5D%20%20%7D)
given that the concentration of hydrogen is doubled we have that
![rate = k [2H_2] [I_2] ----(2)](https://tex.z-dn.net/?f=rate%20%20%3D%20k%20%5B2H_2%5D%20%5BI_2%5D%20----%282%29)
=> ![k = \frac{rate_n }{ [2H_2] [I_2]}](https://tex.z-dn.net/?f=k%20%3D%20%5Cfrac%7Brate_n%20%20%7D%7B%20%5B2H_2%5D%20%5BI_2%5D%7D)
So equating the two k
![\frac{2.0*10^{4}}{[H_2] [I_2] } = \frac{rate_n }{ [2H_2] [I_2]}](https://tex.z-dn.net/?f=%5Cfrac%7B2.0%2A10%5E%7B4%7D%7D%7B%5BH_2%5D%20%5BI_2%5D%20%20%7D%20%3D%20%5Cfrac%7Brate_n%20%20%7D%7B%20%5B2H_2%5D%20%5BI_2%5D%7D)
=>
So when
![[H_2] = 1.8 M](https://tex.z-dn.net/?f=%5BH_2%5D%20%3D%201.8%20M)
![[I_2] = 0.82 \ M](https://tex.z-dn.net/?f=%5BI_2%5D%20%3D%20%200.82%20%5C%20M)
We have
