The equilibrium: 2 NO2(g) \Longleftrightarrow⇔ N2O4(g) has Kc = 4.7 at 100ºC. What is true about the rates of the forwar d (ratefor) and reverse (raterev) reactions initially and at equilibrium if an empty container is filled with just NO2?
1 answer:
Answer:
Initial: forward rate > reverse rate Equilibrium: forward rate = reverse rate Explanation:
2NO₂(g) → N₂O₄(g) Kc=4.7
The definition of <em>equilibrium</em> is when the forward rate and the reverse rate are <em>equal</em>.
Because in the initial state there's only NO₂, there's no possibility for the reverse reaction (from N₂O₄ to NO₂). Thus the forward rate will be larger than the reverse rate.
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