Question

Calculate the centripetal force exerted on the Earth by the Sun. Assume that the period of revolution for the Earth is 365.25 days, the average distance is 1.5 × 10^8 km and the Earth’s mass is 6 × 10^24 kg. The choices are: 1. 3.56775 × 10^22 N 2. 2.66331 × 10^32 N 3. 7.24562 × 10^22 N 4. 1.62932 × 10^21 N5. None of these 6. 3.56775 × 10^19 N 7. 4.6238 × 10^29 N 8. 1.28439 × 10^26 N 9. 7.24562 × 10^20 N

Answer 1

Answer:

Explanation:

The Formula for finding the centripetal force $F_{c}$ is following

$F_{c} = \frac{mv^{2} }{r}$

From the question, mass m and radius r is given. However, we have to find the velocity v;

using formula

$2*π*r=C$

putting values

$C = 2*3.14*(1.5 * 10^{8} * 10^{3} )$

$C= 9.425 * 10^{11}$

Using formula

$C=v*t$

$v=\frac{C}{t} \\v=\frac{9.425*10^{11} }{365.25[tex]*24*60*60$}[/tex]

v = 29866.02m/s

putting in formula of $F_{c}[tex],[tex]F_{c} = \frac{6*10^{24} * 10^{3} * (29866.02^{2} )}{1.5*10^{11} }$

$F_{c} = 3.5679*[tex]10^{22}$