In this problem, we are asked to declare statements that describe the orders given as stated. In the first command, we are to define the element number of the element specified, which by, in this case, is oxygen. This is expressed: Element number = 8. Then we name the element that is element = oxygen. The third command specifies the atomic weight of the elementoxygen = 15.9994. For the last command, the expression is atomic weight = oxygen. It is important to arrange the commands in order so that the program that understands the data executes the orders well and translate them into output.
This means that point P lies on GK where the ratio between the length of GP to the length of PK is:
GP/PK = 2/3
To better understand this, assume that the length of GK is 5 cm. Applying the given ratio, we will find that:
GP = 2 cm and PK = 3cm
You have to keep the same number in the book
Answer :
6 : Margaret has 30 50-cent coins and 26 10-cent coins
let 'x' represent the number of 50-cent coins, then '56-x' represents the number of 10-cent coins
17.60 = 0.5x + 0.1(56-x)
solving for 'x' we have x=30
56-30 = 26
7 : Total money = $29.40
mich money = m dollar,
amy money = (3/4)m dollars,
Total = m + 3m/4 = 29.40,
4m+3m = 4*29.4,
7m = 117.6,
m = 117.6/7 = 16.8
Hence,
Michelle's money = $16.80
Amy money = $12.60
8 : (a) The amount of milk in a carton is normally distributed with a mean of 260 millilitres (mL) and a standard deviation of 8 mL. Every milk carton is labelled with the serving size as 250 mL. (i) What is the probability that a randomly selected carton has more than the labelled serving? [3 marks) (ii) Determine the amount of milk in a carton for which only 7.08% of cartons fall below this amount. [3 marks (iii) Find an interval around the mean y = 260mL such that 95% of all milk cartons fall within this interval. (5 marks)
9 : a=3, b=5
So b+2 = a+4 = 4a-b
b=a+2
3a=b+4
b=2a-1
Hence
2a-1=a+2
10 : original dimensions of rectangle, length = 18cm and width = 10cm
Let length and width = L and W.
from statement "A rectangle has perimeter 56 cm. If 4 cm is taken from the length and added to the width, the rectangle becomes a square", you can deduce
2L + 2W = 56 ( its sides make up its perimeter )
L - 4 = W + 4
L = W + 8
sub L = W + 8 into 2L + 2W = 56
2 ( W + 8 ) + 2W = 56
2W + 16 + 2W = 56
4W = 40
W = 10
sub W = 10 into L = W + 8
L = 10 + 8 = 18
Step-by-step explanation:
may be it is answer.......
