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djverab [1.8K]
3 years ago
9

If two dice are rolled, find the probability of rolling two 6's.

Mathematics
1 answer:
djyliett [7]3 years ago
8 0
Total no. of outcomes when two dice are rolled = 36

No. of outcome when 6 will be on both dice = 1

Probability of rolling two 6's = 1/36

Hope this helps!
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Find the number of integral solutions of x+y +z = 12, where −3 ≤ x ≤ 4, 2 ≤ y ≤ 11, and<br> z ≥ 3.
SashulF [63]

There are 59 integer solutions

Such questions are best solved by writing cases and calculating the total number of cases. So beginning with

1)  x = -3. The possible combinations are as follows:-

-3 2 13

-3 3 12

-3 4 11

-3 5 10

-3 6 9

-3 7 8

-3 8 7

-3 9 6

-3 10 5

-3 11 4

10 combinations

2) x = -2

-2 2 12

through

-2 11 3

10 combinations

3) x = -1

-1 2 11

through

-1 10 3

9 combinations

4) x = 0

0 2 10

through

0 9 3

8 combinations

as we can see from the pattern at x =1  we get 7 combinations, at x =2  we get 6 combinations, at x=3 we get 5 combinations and at x =4  we get 5 combinations.

Thus total number of combinations 4+5+6+7+8+9+10+10 = 59 integer solution.

Learn more about combinations here :

brainly.com/question/13387529

#SPJ1

5 0
2 years ago
Reference angle of 203 degrees
Alex787 [66]
The angle is in the 3rd quadrant so you subtract 180° from it giving you 23° 
5 0
3 years ago
Stella works for a company that makes aluminum cans. A large soup can have a radius of 8 centimeters and a height of 20 centimet
4vir4ik [10]
Could possibly be 36
6 0
3 years ago
I need help asap !!!
Tcecarenko [31]
I cant see the full thing please crop
8 0
3 years ago
Given that log(7) = 0.8451, find the value of the logarithm:<br><br> log (1/7000)
Anni [7]
The solution to the problem is as follows:

<span>log(1/7000)

= log1 - log7000

= -log(7*10^3)

= -log7 + log10^3

= -log7 + 3

= 0.8451 + 3
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
4 0
3 years ago
Read 2 more answers
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