we are ratio as
![=\frac{3}{7}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B3%7D%7B7%7D)
It will be equivalent to only those terms which would be multiple of this term
so, we will multiply top and bottom term by 5
and we get
![=\frac{3\times 5}{7\times 5}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B3%5Ctimes%205%7D%7B7%5Ctimes%205%7D)
![=\frac{15}{7\times 5}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B15%7D%7B7%5Ctimes%205%7D)
![=\frac{15}{35}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B15%7D%7B35%7D)
so, it is very similar to 12/35
so, it will be equivalent to 12/35
so, option-C.......Answer
Answer:
2
Step-by-step explanation:
Answer:
-10/77
Step-by-step explanation:MaTh
answer
i
explanation
note that i =
and that ![\sqrt{ab} =\sqrt{a} *\sqrt{b}](https://tex.z-dn.net/?f=%5Csqrt%7Bab%7D%20%3D%5Csqrt%7Ba%7D%20%2A%5Csqrt%7Bb%7D)
![\sqrt{11} - \sqrt{-31}](https://tex.z-dn.net/?f=%5Csqrt%7B11%7D%20-%20%5Csqrt%7B-31%7D)
= ![\sqrt{11} - \sqrt{31 * -1}](https://tex.z-dn.net/?f=%5Csqrt%7B11%7D%20-%20%5Csqrt%7B31%20%2A%20-1%7D)
= ![\sqrt{11} - \sqrt{31}*\sqrt{-1}](https://tex.z-dn.net/?f=%5Csqrt%7B11%7D%20-%20%5Csqrt%7B31%7D%2A%5Csqrt%7B-1%7D)
=
i
note that the i is outside of the square root