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Alenkinab [10]
2 years ago
14

Simplify the problem pleaseee

Mathematics
1 answer:
ladessa [460]2 years ago
8 0

Answer:

16x²+6x+3

Step-by-step explanation:

x²+6x+3(5x²-4)+15

x²+6x+15x²-12 +15

16x²+6x+3

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5 0
3 years ago
Read 2 more answers
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vekshin1
P=22 rewrite the question as -8+p/11=-6 then move all terms not containing p to the right side p/11=2 multiply both sides of the given equation by 11, the reciprocal, 11*p/11=11*2
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Solve the equation, justify<br> each step with an algebraic<br> property.<br> 7 = 16 + 3x
GenaCL600 [577]
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5 0
3 years ago
A triangular lot has sides of 215m, 185m, and 125m. Find the measures of the angles at its corners
Vlada [557]

Answer:

The measures of the angles at its corners are 59.1\°,35.4\°,85.5\°

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle A

Applying the law of cosines

185^{2}= 215^{2}+125^{2}-2(215)(125)cos(A)

2(215)(125)cos(A)= 215^{2}+125^{2}-185^{2}

cos(A)= [215^{2}+125^{2}-185^{2}]/(2(215)(125))cos(A)=0.513953

A=arccos(0.513953)=59.1\°

step 2

Find the measure of angle B

Applying the law of cosines

125^{2}= 215^{2}+185^{2}-2(215)(185)cos(B)

2(215)(185)cos(B)= 215^{2}+185^{2}-125^{2}

cos(B)= [215^{2}+185^{2}-125^{2}]/(2(215)(185))cos(B)=0.81489

B=arccos(0.81489)=35.4\°

step 3

Find the measure of angle C

Applying the law of cosines

215^{2}= 125^{2}+185^{2}-2(125)(185)cos(C)

2(125)(185)cos(C)= 125^{2}+185^{2}-215^{2}

cos(C)= [125^{2}+185^{2}-215^{2}]/(2(125)(185))cos(C)=0.0784

C=arccos(0.0784)=85.5\°

3 0
3 years ago
How do you find area of a trapezoid I will mark brainliest for the most explained and simple answer!!!!
kakasveta [241]

Answer:

A = ((a+b)/2)h

Step-by-step explanation:

a and b are base (the top and bottom)

h is height

7 0
3 years ago
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