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AURORKA [14]
3 years ago
15

3. What are transition metals?

Chemistry
2 answers:
brilliants [131]3 years ago
7 0

Answer:

to

Explanation:

3241004551 [841]3 years ago
6 0
They are metals found in the middle of the periodic table and are in the d block
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Balancing the reaction by oxidation number method k2cr2o7+sncl2+hcl​
Mumz [18]

Answer:

K_2Cr_2O_7 (aq) + 14 HCl (aq) + 3 SnCl_2 (aq)\rightarrow 2 CrCl_3 (aq) + 7 H_2O (l) + 3 SnCl_4 (aq) + 2 KCl (aq)

Explanation:

The products of this reaction are given by:

K_2Cr_2O_7 (aq) + SnCl_2 (aq) + HCl (aq)\rightarrow KCl (aq) + SnCl_4 (aq) + CrCl_3 (aq) + H_2O (l)

Firstly, dichromate anion becomes chromium(III) cation, let's write this change:

Cr_2O_7^{2-} (aq)\rightarrow Cr^{3+} (aq)

The following steps should be taken:

  • balance the main element, chromium: multiply the right side by 2 to get 2 chromium species on both side:

Cr_2O_7^{2-} (aq)\rightarrow 2 Cr^{3+} (aq)

  • balance oxygen atoms by adding 7 water molecules on the right:

Cr_2O_7^{2-} (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)

  • balance the hydrogen atoms by adding 14 protons on the left:

Cr_2O_7^{2-} (aq) + 14 H^+ (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)

  • balance the charge (the total net charge on the left is 12+, on the right we have 6+, so 6 electrons are needed on the left):

Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 6e^-\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)

Similarly, tin(II) cation becomes tin(IV) cation:

Sn^{2+} (aq)\rightarrow Sn^{4+} (aq) + 2e^-

Now that we have the two half-equations, multiply the second one by 3, so that it also has 6 electrons that will be cancelled out upon addition of the two half-equations:

Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 6e^-\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)

3 Sn^{2+} (aq)\rightarrow 3 Sn^{4+} (aq) + 6e^-

Add them together:

Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 3 Sn^{2+} (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l) + 3 Sn^{4+} (aq)

Adding the ions spectators:

K_2Cr_2O_7 (aq) + 14 HCl (aq) + 3 SnCl_2 (aq)\rightarrow 2 CrCl_3 (aq) + 7 H_2O (l) + 3 SnCl_4 (aq) + 2 KCl (aq)

7 0
3 years ago
An object has a mass of 2800g and a volume of 3cm3. What is its density?<br>​
jeka57 [31]

Answer:

933.33 g/cm³

Explanation:

Density = mass / volume

Density = 2800/3 = 933.3 g/cm³.

4 0
3 years ago
if the particles formed through fission have less mass than the starting material has the laaw of conversation of energy been br
Alexxandr [17]

The law of conservation of energy has not been broken, provided energy is released from the fission process.

<h3>What is the law of conservation of energy?</h3>

The law states that the total energy of a process is conserved. That is, the total energy or mass of a system before and after undergoing processing remains the same. However, some of the mass/energy can be converted to another form.

When a material undergoes fission, the sum total of the mass of the particles formed should be equal to the mass of the starting materials, provided that all other things remain the same.

However, if energy is released from the fission process, it means that some of the mass of the starting materials has been converted to energy and released to the environment.

More on the law of conservation of energy can be found here: brainly.com/question/20971995

#SPJ1

3 0
2 years ago
Which of the following describes scientists?
serious [3.7K]
I believe the answer I’d D

Hope it helps
3 0
3 years ago
2. A block of aluminum with a mass of 140g is cooled from 98.4oC to 62.2oC with a release of 1137J of heat. From these data, cal
NeTakaya
Q =  M * C *ΔT

Q / <span>ΔT  = M

</span>Δf - Δi =  98.4ºC - 62.2ºC = 36.2ºC
<span>
C = 1137 J / 140 * 36.2

C = 1137 / 5068

C = 0.224 J/gºC</span>
8 0
3 years ago
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