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ELEN [110]
2 years ago
6

Can someone help please!

Chemistry
1 answer:
kirill [66]2 years ago
6 0
Base isolation is a technique used by engineers to help prevent damage to buildings by volcanoes. The
O main structure of the building is separate from the base, which allows lava to pass under the building
without causing much damage
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A barium atom attains a stable electron configuration when it bonds with?
adell [148]
The answer is B. two chlorine atoms.
The chemical formula of the compound is BaCl2~

6 0
3 years ago
From a 2.875 g sample containing only iron, sand, and salt, 0.660 g of iron and 1.161 g of sand were separated and recovered. Wh
Serjik [45]

Answer:

36.66%

Explanation:

Step 1: Given data

  • Mass of iron: 0.660 g
  • Mass of sand: 1.161 g
  • Mass of the sample: 2.875 g
  • Mass of salt: ?

Step 2: Calculate the mass of salt

The mass of the sample is equal to the sum of the masses of the components.

m(sample) = m(iron) + m(sand) + m(salt)

m(salt) = m(sample) - m(iron) - m(sand)

m(salt) = 2.875 g - 0.660 g - 1.161 g

m(salt) = 1.054 g

Step 3: Calculate the percent of salt in the sample

We will use the following expression.

%(salt) = m(salt) / m(sample) × 100%

%(salt) = 1.054 g / 2.875 g × 100% = 36.66%

7 0
3 years ago
Science 7 Grade 7. Can anyone please help me answer these science questions?
masha68 [24]
A cellphone battery is a electrical energy 
and a piston in an engine is an thermal energy
6 0
3 years ago
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A flexible container at an initial volume of 6.13 L contains 2.51 mol of gas. More gas is then added to the container until it r
aleksley [76]

Answer:

2.12 moles of gas were added.

Explanation:

We can solve this problem by using<em> Avogadro's law</em>, which states that at constant temperature and pressure:

  • V₁n₂=V₂n₁

Where in this case:

  • V₁ = 6.13 L
  • n₂ = ?
  • V₂ = 11.3 L
  • n₁ = 2.51 mol

We <u>input the data</u>:

  • 6.13 L * n₂ = 11.3 L * 2.51 mol
  • n₂ = 4.63

As <em>4.63 moles is the final number of moles</em>, the number of moles added is:

  • 4.63 - 2.51 = 2.12 moles
5 0
3 years ago
How many atoms are contained in 5.77 grams of aluminum? Express your answer in exponential notation (Ex: 6.02*1023 would be ente
bagirrra123 [75]

Answer:

5.09

Explanation:

6 0
3 years ago
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