Answer: The reaction for the $K_{sp}$ value of lead phosphate is given below and the value of solubility product for the same is $3.0\rightarrow 10^{-44}$

Explanation:

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio. It is expressed as $K_{sp}$

The chemical formula of lead phosphate is $Pb_3(PO_4)_2$

The equation for the hydration of the lead phosphate is given as:

$Pb_3(PO_4)_2(s)+H_2O(l)\rightarrow 3Pb^{2+}(aq.)+2PO_4^{3-}(aq.)$

The solubility product of lead phosphate is $3.0\rightarrow 10^{-44}$ . This means that it is highly insoluble in water as the solubility product is very very low.

Hence, the reaction for the $K_{sp}$ value of lead phosphate is given above and the value of solubility product for the same is $3.0\rightarrow 10^{-44}$

4 0

3 years ago

Decane (C10H22) used to produce poly(ethene). what conditions are needed?

Strike441 [17]

Cracking of hydrocarbons involves thermal decomposition.
This means that large hydrocarbon molecules break into
smaller molecules when they are heated. The hydrocarbons
are boiled and the hydrocarbon gases are either
mixed with steam and heated to a very high temperature or
passed over a hot powdered aluminium oxide catalyst.
The catalyst works by providing the hydrocarbon gases
with a convenient surface for the cracking to take place.

For example, decane (an alkane with 10 carbons)
can be cracked to produce octane and ethene.

decane octane + ethene.
C10H22(g) C8H18(g) + C2H4(g)

Octane is used as petrol.
Ethene is used in the manufacture of polymers.

Cracking an alkane produces a smaller alkane plus an alkene.
If you add up the number of hydrogen atoms in the
above reaction, you will see that there are 22 on each side.
An alkene is produced because the original alkane does
not have enough hydrogen atoms to produce two more alkanes.

hope this helps

6 0

2 years ago