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kiruha [24]
3 years ago
12

Which segment is the altitudes of the pyramid?

Mathematics
2 answers:
Fittoniya [83]3 years ago
6 0
The altitude of a pyramid is the perpendicular distance from the vertex to the plane of the base.
NikAS [45]3 years ago
5 0
Altitude of a pyramid is the perpendicular distance from the vertex to the plane of the base. Base can be regular or irregular in pyramid. In regular pyramid, altitude and the slant height of a pyramid are not the same as the slant height is the length of the face of the pyramid. Altitude meets the base at its center.
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There are eleven songs on your playlist. five of them are country and six are pop. with random shuffle and no repetition, you li
jek_recluse [69]
The probability is 1/462.

To find this, we will find the number of combinations of 5 country songs taken 5 at a time, 6 pop songs taken 0 at a time, and the total number of outcomes will be 11 songs taken 5 at a time:

\frac{_5C_5\times_6C_0}{_{11}C_5}
\\
\\\frac{\frac{5!}{5!0!}\times\frac{6!}{0!6!}}{\frac{11!}{5!6!}}=\frac{1\times1}{\frac{11!}{5!6!}}
\\
\\=\frac{1}{462}
3 0
3 years ago
I need this solved as c.l.t<br> 6=n-2n
Shtirlitz [24]

Answer:

n= -6

Step-by-step explanation:

3 0
2 years ago
Is the square root of 42 rational or irrational? Explain
MA_775_DIABLO [31]

<em>☽------------❀-------------☾</em>

<em>Hi there!</em>

<em>~</em>

\sqrt{42}<em> ≈ </em>6.4807406984087...

<em>So </em>\sqrt{42}<em> is irrational (since the decimal portion doesn't terminate or repeat) </em>

<em>❀Hope this helped you!❀</em>

<em>☽------------❀-------------☾</em>

(The other person copied there answer from google!)

5 0
3 years ago
What is the slope of the line shown below?<br> A. -2/3<br> B.-3/2<br> C. 3/2<br> D. 2/3
Annette [7]

Answer:

-2/3

Step-by-step explanation:

5 0
2 years ago
An object is thrown upward at a speed of 124 feet per second by a machine from a height of 19 feet off the ground. The height h
klasskru [66]

a) For this question we set h=59 and solve for t, in order to do so we use the general formula for second-degree equations:

\begin{gathered} t=\frac{-124\pm\sqrt[]{124^2-4(-16)(-40)}}{2(-16)} \\ t=\frac{-124\pm113.21}{-32} \end{gathered}

The height of the object will be 59 feet at t=7.41 seconds and t=0.34 seconds.

b) When the object reaches the ground, h=0 therefore:

0=-16t^{2}+124t+19

Solving for t we get:

\begin{gathered} t=\frac{-124\pm\sqrt[]{124^2-4(-16)(19)}}{2(-16)} \\ t=\frac{-124\pm\sqrt[]{16592}}{-32}=\frac{-124\pm128.81}{-32} \end{gathered}

Therefore, since t cannot be negative the solution is t=7.9 seconds.

7 0
1 year ago
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