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kiruha [24]
3 years ago
12

Which segment is the altitudes of the pyramid?

Mathematics
2 answers:
Fittoniya [83]3 years ago
6 0
The altitude of a pyramid is the perpendicular distance from the vertex to the plane of the base.
NikAS [45]3 years ago
5 0
Altitude of a pyramid is the perpendicular distance from the vertex to the plane of the base. Base can be regular or irregular in pyramid. In regular pyramid, altitude and the slant height of a pyramid are not the same as the slant height is the length of the face of the pyramid. Altitude meets the base at its center.
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Car is moving on a circle on a plane. At time t (seconds), its x-coordinate is given by x(t) = 10 sin(200t + 3) + 30 while its y
Aleks [24]

Answer:

we have centre of circle as (30,40) and radius = 1

Step-by-step explanation:

Given that a car is moving on a circle on a plane.

At time t (seconds),

x(t) = 10 sin(200t + 3) + 30

and

y(t) = 10 cos(200t + 3) + 40

x-30 = 10 sin(200t + 3) \\y-40 = 10 cos(200t + 3) + 40

when we square and add both the equations we get

(x-30)^2 + (y-40)^2 = 1

(since sin square + cos square = 1 always)

i.e. we have centre of circle as (30,40) and radius = 1

3 0
3 years ago
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tino4ka555 [31]

Answer:

\large\boxed{x=\dfrac{1}{2}-\sqrt2\ or\ x=\dfrac{1}{2}+\sqrt2}

Step-by-step explanation:

\text{The quadratic formula of}\ ax^2+bx+c=0:\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

\text{We have:}\\\\4x^2-7=4x\qquad\text{subtract}\ 4x\ \text{from both sides}\\\\4x^2-4x-7=0\\\\a=4,\ b=-4,\ c=-7\\\\b^2-4ac=(-4)^2-4(4)(-7)=16+112=128\\\\\sqrt{b^2-4ac}=\sqrt{128}=\sqrt{64\cdot2}=\sqrt{64}\cdot\sqrt2=8\sqrt2\\\\x=\dfrac{-(-4)\pm8\sqrt2}{(2)(4)}=\dfrac{4\pm8\sqrt2}{8}\qquad\text{simplify by 4}\\\\x=\dfrac{1\pm2\sqrt2}{2}\to x=\dfrac{1}{2}\pm\sqrt2

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3 years ago
What number is 30% of 90​
marta [7]

Answer:

it is 27 as you multiply .30 times 90

3 0
3 years ago
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It would be A because -2 times +6 equals -12
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