Answer:
C.
Explanation:
Option C
The information given in the question tells us about the number of electrons in an atom and also the number of shells in the atom. So, we will come to know about the atomic number, size and chemical properties of the atom. But we cannot determine atomic mass. Atomic mass is a function of number of neutrons and protons.
Answer:
A.) 3605.6 N
B.) 33.7 degree
Explanation:
To find the result force acting on the wing of the airplane, we need to resolve the forces into x and y components
Resolving into x component :
Sum of forces = 3500 - 500 = 3000N
Resolving into y component:
Sum of forces = 2000N
Resultant force Fr = sqrt ( Fx^2 + Fy^2)
Fr = sqrt ( 3000^2 + 2000^2 )
Fr = sqrt ( 9000000 + 4000000 )
Fr = sqrt ( 13000000)
Fr = 3605.6 N
Therefore, resultant force acting on the wing is 3605.6 N
The direction of the vector will be:
Tan Ø = Fy / Fx
Substitute Fx and Fy into the formula
Tan Ø = 2000 / 3000
Tan Ø = 0.66666
Ø = tan^-1(0. 66666)
Ø = 33.7 degree.
While falling, both the sheet of paper and the paper ball experience air resistance. But the surface area of the sheet is much more than that of the spherical ball. And air resistance varies directly with surface area. Hence the sheet experiences more air resistance than the ball and it falls more slowly than the paper ball.
Hope that helps!
Answer:
Part 1) Time of travel equals 61 seconds
Part 2) Maximum speed equals 39.66 m/s.
Explanation:
The final speed of the train when it completes half of it's journey is given by third equation of kinematics as

where
'v' is the final speed
'u' is initial speed
'a' is acceleration of the body
's' is the distance covered
Applying the given values we get

Now the time taken to attain the above velocity can be calculated by the first equation of kinematics as

Since the deceleration is same as acceleration hence the time to stop in the same distance shall be equal to the time taken to accelerate the first half of distance
Thus total time of journey equals
Part b)
the maximum speed is reached at the point when the train ends it's acceleration thus the maximum speed reached by the train equals 
<span>Answer:
Using 1/f = 1/d' + 1/d ...(where d' object distance and d is image distance)
1/4 = 1/7 + 1/d
1/4 - 1/7 = 1/d
3/28 = 1/d
d = 28/3
d = 9.33 cm</span>