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azamat
3 years ago
12

Rjejdndjoskdnrksjdjsjsne

Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
4 0
Rjejdndjoskdnrksjdjsjsne
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1. Predict whether the energy required to remove an electron from magnesium and potassium would be more or less than that requir
Inga [223]

In both cases less energy is required

But comparetively Mg require more energy than K

Let's see the electron configuration of Both

  • [Mg]=1s²2s²2p⁶3s²=[Ne]3s²
  • [K]=1s²2s²2p⁶3s²3p⁶4s¹=[Ar]4s¹

K has only one valence electron so very less ionization enthalpy so less energy required

Mg has 2 so more IE hence more energy required

8 0
1 year ago
What’s an example of contact friction
kotegsom [21]

Answer:

a nightstand on a lamp table

Explanation:

5 0
3 years ago
The yellow star has much less mass the blue star and so who will live longer
In-s [12.5K]

The yellow star will live longer as it has less mass

8 0
3 years ago
The rotational speed of earth is similar to?​
m_a_m_a [10]
Actually, the speed of the earth is the same everywhere, taking the angular speed as the valid measure of the speed
8 0
3 years ago
In some cases, neither of the two equations in the system will contain a variable with a coefficient of 1, so we must take a fur
Margaret [11]

Answer:

D = -4/7 = - 0.57

C = 17/7 = 2.43

Explanation:

We have the following two equations:

3C + 4D = 5\ --------------- eqn (1)\\2C + 5D = 2\ --------------- eqn (2)

First, we isolate C from equation (2):

2C + 5D = 2\\2C = 2 - 5D\\C = \frac{2 - 5D}{2}\ -------------- eqn(3)

using this value of C from equation (3) in equation (1):

3(\frac{2-5D}{2}) + 4D = 5\\\\\frac{6-15D}{2} + 4D = 5\\\\\frac{6-15D+8D}{2} = 5\\\\6-7D = (5)(2)\\7D = 6-10\\\\D = -\frac{4}{7}

<u>D = - 0.57</u>

Put this value in equation (3), we get:

C = \frac{2-(5)(\frac{-4}{7} )}{2}\\\\C = \frac{\frac{14+20}{7}}{2}\\\\C = \frac{34}{(7)(2)}\\\\C =  \frac{17}{7}\\

<u>C = 2.43</u>

5 0
3 years ago
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