Answer:
(C) greater than zero but less than 45° above the horizontal
Explanation:
The range of a projectile is given by R = v²sin2θ/g.
For maximum range, sin2θ = 1 ⇒ 2θ = sin⁻¹(1) = 90°
2θ = 90°
θ = 90°/2 = 45°
So the maximum horizontal distance R is in the range 0 < θ < 45°, if θ is the angle above the horizontal.
Longitudinal waves have energy that vibrates parallel to the medium - a compression is the region of greatest density and the rarefaction the region of highest density .The rarefaction (much like the maximum amplitude in a transverse wave) has a region of lowest density, typically situated in the exact center of the region.
Answer:
B, A, A, B
Explanation:
Just trust me on this one.
Answer:
d = 6.43 cm
Explanation:
Given:
- Speed resistance coefficient in silicon n = 3.50
- Memory takes processing time t_p = 0.50 ns
- Information is to be obtained within T = 2.0 ns
Find:
- What is the maximum distance the memory unit can be from the central processing unit?
Solution:
- The amount of time taken for information pulse to travel to memory unit:
t_m = T - t_p
t_m = 2.0 - 0.5 = 1.5 ns
- We will use a basic relationship for distance traveled with respect to speed of light and time:
d = V*t_m
- Where speed of light in silicon medium is given by:
V = c / n
- Hence, d = c*t_m / n
-Evaluate: d = 3*10^8*1.5*10^-9 / 3.50
d = 0.129 m 12.9 cm
- The above is the distance for pulse going to and fro the memory and central unit. So the distance between the two is actually d / 2 = 6.43 cm
