Answer:11686.5 joules
Explanation:
elastic constant(k)=53N/m
extension(e)=21m
Elastic potential energy=(k x e^2)/2
Elastic potential energy=(53 x (21)^2)/2
Elastic potential energy=(53x21x21)/2
Elastic potential energy=23373/2
Elastic potential energy=11686.5
Elastic potential energy is 11686.5 joules
In a closed system, the loss of momentum of one object is same as________ the gain in momentum of another object
according to law of conservation of momentum, total momentum before and after collision in a closed system in absence of any net external force, remains conserved . that is
total momentum before collision = total momentum after collision
P₁ + P₂ = P'₁ + P'₂
where P₁ and P₂ are momentum before collision for object 1 and object 2 respectively.
P'₁ - P₁ = - (P'₂ - P₂)
so clearly gain in momentum of one object is same as the loss of momentum of other object
Answer:
5.33kg
Explanation:
Given parameters:
Velocity of eagle = 15m/s
Kinetic energy of the eagle = 600J
Unknown:
Mass of the eagle = ?
Solution:
The kinetic energy of any body is the energy due to the motion of a body. There are different forms of kinetic energy some of which are thermal, mechanical, electrical energy.
The formula of kinetic energy is given as;
Kinetic energy = 
m v²
where m is the mass, V is the velocity
substitute the parameters in the equation;
600 = x m x 15²
225m = 1200
m = 
= 5.33kg
A: Buoyant force is equal to the weight
Answer:
<h2>FUNDAMENTAL UNITS INVOLVED ARE : NEWTON AND SECOND .</h2>
<h2>FORMULA OF PRESSURE = </h2>
<h2>P=F/A </h2>
