Answer:
eazy
Explanation:
hi bro it is very hard so I can't help and I don't the answer
Answer:
48.26 m
Explanation:
time to goes up (till stop for a while in the air - maximum height)
vt = vo + a t
0 = 15 + g . t
0 = 15 + (-9.8) . t
9.8t = 15
t = 1.531 s
so the time left to goes down is
4.0 - 1.531 = 2.469 s
height from the top of building can find it by using
vo =√(2gh)
15 = √(2)(9.8).h
15² = 19.6h
h = 225/19.6 = 11.48 m
so the distance of maximum height to the ground is
t = √(2H/g)
2.469 = √(2H/9.8)
2.469² = 2H/9.8
6.096 = 2H/9.8
2H = 6.096 x 9.8 = 59.74 m
so the vertical distance of the building (or the building height's is)
H - h = 59.74 - 11.48 = 48.26 m
Answer: 1872 N
Explanation:
This problem can be solved by using one of the Kinematics equations and Newton's second law of motion:
(1)
(2)
Where:
is the bullet's final speed (when it leaves the muzzle)
is the bullet's initial speed (at rest)
is the bullet's acceleration
is the distance traveled by the bullet before leaving the muzzle
is the force
is the mass of the bullet
Knowing this, let's begin by isolating from (1):
(3)
(4)
(5)
Substituting (5) in (2):
(6)
Finally:
