Answer:
Explanation:
change in flux = no of turns x area of loop x change in magnetic field
= 1 x π 65² x 10⁻⁶ x ( 650 - 350 ) x 10⁻³
= 3.9 x 10⁻³ weber .
rate of change of flux = change of flux / time
= 3.9 x 10⁻³ / .10
= 39 x 10⁻³ V
= 39 mV .
Since the magnetic flux is directed outside page and it is increasing , induced current will be clockwise so that magnetic field is produced in opposite direction to reduce it , as per Lenz's law.
Answer:
The starting velocity for ball 1 is 1.00 meter/second. Its ending velocity is 0.25 meter/second.
The change in velocity for ball 1 is 0.25 – 1.00 = -0.75 meter/seconds
The formula we can use in this case is:
d = v0t + 0.5 at^2
v = at + v0
where,
d = distance travelled
v0 = initial velocity = 0 since at rest
t = time travelled
a = acceleration
v = final velocity when it took off
a. d = 0 + 0.5 * 3 * 30^2
d = 1350 m
b. v = 3 * 30 + 0
<span>v = 90 m/s</span>
Before the engines fail 
, the rocket's horizontal and vertical position in the air are
and its velocity vector has components
After 
, its position is
and the rocket's velocity vector has horizontal and vertical components
After the engine failure 
, the rocket is in freefall and its position is given by
and its velocity vector's components are
where we take 
.
a. The maximum altitude occurs at the point during which 
:
At this point, the rocket has an altitude of
b. The rocket will eventually fall to the ground at some point after its engines fail. We solve 
for 
, then add 3 seconds to this time:
So the rocket stays in the air for a total of 
.
c. After the engine failure, the rocket traveled for about 34.6 seconds, so we evalute 
for this time :
<u>Answer</u>:
Effort is the unaltered force. Load is the altered force.
