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IrinaVladis [17]
3 years ago
14

according to newton's third law, when a horse pulls on a cart, the cart pulls back on the horse with an equal force on the horse

. if in fact the cart pulls back on the horse as hard as the horse pulls forward on the cart, how is it possible for the horse to move the cart?
Physics
1 answer:
Debora [2.8K]3 years ago
8 0
Based on Newton's principle, whenever objects A and B interact with each other, they exert forces upon each other.

When a horse pulls on a cart, t<span>he horse exerts a force only to the cart. But that force applies only to the cart, not to the horse.
 
The cart in turn exerts a force on the horse. But that force applies only to the horse, not the cart also.
</span>
There are two forces resulting from this interaction - a force on the horse and a force on the cart. T<span>he net force on the cart remains as it was --- a positive force in the direction of the horse's movement. Therefore, the cart begins to accelerate and move.</span><span>


</span>
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We want to see how the time will be affected 
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to solve for ' t '.                                                      D  =  (1/2) (g) (t²)

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Divide each side by ' g ' :      2 D/g =                  t² 

Square root each side:        t = √ (2D/g)

Looking at the equation now, we can see what happens to ' t ' when only ' g ' changes:

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They don't change by the same factor, because  1/g  is inside the square root.  So 't' changes the same amount as  √1/g  does.

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It would take the same bottle  (2.45 x 4.95) = 12.12 seconds to roll off the same window sill and fall 120 meters down to the surface of the Moon.
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Answer:

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hope this helps

brainliest appreciated

good luck! have a nice day!

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