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dangina [55]
3 years ago
11

Is it possible for an object to have a charge of 4.8x10-9 C? Why or why not?

Physics
1 answer:
Gelneren [198K]3 years ago
3 0
I have absolutely no clue
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Riley is cleaning his room(a once a year activity) and pulls the Hoover with a force of 8 N a total distance of 20 metres. How m
Radda [10]

Answer:

160J

Explanation:

Given force = 8N and total distance = 20 meters

Workdone = force x distance

= 8 x 20

= 160J

Therefore, workdone by Riley in pulling the hoover is 160J

7 0
3 years ago
A bat hits a moving baseball. If the bat delivers a net eastward impulse of 1.3 N-s and the ball starts with an initial horizont
Georgia [21]

Answer:

141.30grams

Explanation:

First, denote our known values;

J=1.3N-s(+,east)\\u=-3.8ms^-^1(-,west)\\v=5.4ms^-^1(+,east)\\m=?

Mass is impulse divided by change in velocity:

m=\frac{J}{v-u}\\=\frac{1.3}{5.4--3.8}\\\\=\frac{1.3}{9.2}\\=0.1413Kgs

Hence, the mass of the ball is 141.30grams

3 0
3 years ago
Machmer Hall is 400 m North and 180 m West of Witless.
yan [13]

Answer:

The distance from Witless to Machmer is 438.63 m.

Explanation:

Given that,

Machmer Hall is 400 m North and 180 m West of Witless.

We need to calculate the distance

Using Pythagorean theorem

D = \sqrt{(d_{m})^2+(d_{w})^2}

Where, d_{m} =distance of Machmer Hall

d_{w} =distance of Witless

Put the value into the formula

D = \sqrt{(400)^2+(180)^2}

D=438.63\ m

Hence, The distance from Witless to Machmer is 438.63 m.

5 0
3 years ago
The series in the He spectrum that corresponds to the set of transitions where the electron falls from a higher level to the nf
Galina-37 [17]
Ok so here is the thing. It is necessary to introduce the atomic number Z into the following equation and the reason for that is that we are not working here with hydrogen (H). It will go like this:  
<span>E=(2.18×10^-18 J)(Z^2 )|1/(ni^2 )-1/(nf^2 )| </span>
<span>E=(2.18×10^-18 J)(2^2 )|1/(6 ^2 )-1/(4 ^2 )|=3.02798×10^-19 J </span>

<span>After that we need to plug the E value calculated into the equation. Remember that the wavelength is always positive:</span>

<span>E=hc/λ 3.02798×10^-19 J=hc/λ λ=6.56×10^-7 m </span>

so 6.56×10^-7 m or better written 656 nm is in the visible spectrum
7 0
3 years ago
Consider two wind turbines, each located in sites with the same wind speed, and each with the same efficiency. Turbine 1 has a r
Alex787 [66]

Answer:

shut up nerd

Exption:

7 0
3 years ago
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