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dangina [55]
3 years ago
11

Is it possible for an object to have a charge of 4.8x10-9 C? Why or why not?

Physics
1 answer:
Gelneren [198K]3 years ago
3 0
I have absolutely no clue
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Indicar objetosque puedan ser observados a simple vista, con microscopio, con microscopio electrico y con miscroscopio de transm
AysviL [449]

Answer:

En esta respuesta voy a usar la unidad μm, tal que:

1 μm = 1*10^(-9) m

Objetos que pueden ser observados a simple vista:

Son todos aquellos objetos que podemos observar simplemente con nuestros ojos, con ellos podemos observar desde un edificio (con tamaños de decenas de metros) hasta algunos cabellos, que pueden tener un diámetro de 0.1 mm

Cosas más pequeñas que estás muy difícilmente se pueden ver a simple vista.

Con un microscopio podremos ver cosas del tamaño de una célula, como glóbulos blancos, rojos, algunos microorganismos, etc, los cuales rondan un tamaño de unos 10 μm. Naturalmente, distintos microscopios tendrán distintas amplificaciones (por lo que con algunos podremos ver objetos muy pequeños que con otros no).

Microscopio eléctrico:

Este microscopio usa electrones en lugar de luz para formar imágenes.

Con él podremos observar cosas como las componentes de una célula (membranas, orgánulos grandes, etc), los cuales pueden medir unos pocos nanómetros (por ejemplo, una membrana celular tendrá un tamaño de entre 5 μm y 10 μm)

Microscopio de transmisión.

Tener en cuenta que el microscopio de transmisión es un microscopio eléctrico, el cual lanza un haz de electrones al objeto que se desea observar, de tal forma que algunos de estos electrones rebotan formando así la imagen virtual amplificada que podemos observar.

Con estos aparatos podemos ver orgánulos pequeños (0.5 μm), y lo más pequeño que podemos ver (con los microscopios más potentes) son columnas de átomos (0.1 μm)

6 0
3 years ago
A 2 kilogram mass is lifted 4 meters above the ground what is the change it gravitational energy
lianna [129]

Answer:

78.4 J

Explanation:

The gravitational potential energy of an object is the energy possessed by the object due to its location in the gravitational field.

The change in gravitational potential energy of an object is given by:

\Delta U=mg\Delta h

where:

m is the mass of the object

g=9.8 m/s^2 is the acceleration due to gravity

\Delta h is the change in height of the object

For the mass in  this problem, we have:

m = 2 kg is the mass

\Delta h = 4 m is the change in height

So, its change in gravitational energy is:

\Delta U=(2)(9.8)(4)=78.4 J

6 0
3 years ago
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