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Furkat [3]
3 years ago
5

Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions:

Chemistry
1 answer:
maxonik [38]3 years ago
7 0

Answer:

$ CaCl_2$, CaS, $ Cr Cl_4$, $ CrS_2$

Explanation:

The reaction can be done by adding the cations and the anions.

The binary compounds are always formed by the two different elements.

When one calcium ion, $ Ca ^{2+} $ combines with the two calcium ions, $ Cl^-$, they formed a binary compound of $ CaCl_2$.

When one $ Ca ^{2+} $ combines with one $S^{2-}$ ion, they formed CaS binary compound.

When one chromium ion $ Cr^{4+}$ combines with four ions of chlorine, $ Cl ^- $, the compound formed is $ Cr Cl_4$.

When 1 ion of $ Cr^{4+}$ combines with 2 ions of sulphur, $S^2$, the binary compound formed is $ CrS_2$.

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Answer:

pH of buffer =4.75

Explanation:

The pH of buffer solution is calculated using Henderson Hassalbalch's equation:

pH=pKa+log[\frac{[salt]}{[acid]}

Given:

pKa = 3.75

concentration of acid = concentration of formic acid = 1 M

concentration of salt =  concentration of sodium formate = 10 M

pH=3.75+log[\frac{10}{1}]=3.75+1=4.75

pH of buffer =4.75

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4 years ago
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3 years ago
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3 years ago
In the reaction Mg (s) + 2HCl (aq) H2 (g) + MgCl2 (aq), how many moles of hydrogen gas will be produced from 75.0 milliliters of
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HCl is <span>limiting reactant, Mg in excess therefore:

</span><span>number of moles HCl:

75.0 mL in liters: 75.0 / 1000 => 0.075 L

Molarity HCl = 1.0 M

n = M x V

n = 1.0 x 0.075 

n = 0.075 moles of HCl

</span>Mg(s) + 2 HCl (aq) = H2 (g) + MgCl2 (aq)

<span>2 moles HCl  -------------------- 1 mole H2
</span><span>0.075 moles of HCl ------------ ( moles H2)
</span>
moles H2 = 0.075 x 1 / 2

moles H2 = 0.075 / 2

= 0.0375 moles of H2

hope this helps!

<span>

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8 0
3 years ago
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