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3 years ago

How many neutrons does element X have if its atomic number is 22 and its mass number is 70?

Chemistry

2 answers:

IRINA_888 [86]3 years ago

7 0

It would have 48 neutrons. :)

Alika [10]3 years ago

5 0

<h2>Answer:</h2>

<u>The number of neutrons is </u><u>48</u>

<h2>Explanation:</h2>

As we know that the atomic number is the number of protons. If we subtract the atomic number from the mass number, we can actually find the number of neutrons.

Number of neutrons = Mass number - atomic number

Neutrons = 70 - 22 = 48

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6c.Calculate the maximum volume, in dm3, of chlorine gas at Stp that can be obtained from 23.4 tonnes of molten sodium chloride.

sweet [91]

Answer:

4.48×10⁶ dm³

Explanation:

We'll begin by converting 23.4 tonnes to grams (g). This can be obtained as follow:

1 tonne = 10⁶ g

Therefore,

23.4 tonnes = 23.4 × 10⁶

23.4 tonnes = 2.34×10⁷ g

Thus, 23.4 tonnes is equivalent to 2.34×10⁷ g

Next, we shall determine the number of mole in 2.34×10⁷ g of NaCl. This can be obtained as follow:

Mass NaCl = 2.34×10⁷ g

Molar mass of NaCl = 58.5 g/mol

Mole of NaCl =?

Mole = mass / molar mass

Mole of NaCl = 2.34×10⁷ / 58.5

Mole of NaCl = 4×10⁵ moles

Next, we shall determine the number of mole of chlorine, Cl₂ produced from the reaction. This can be obtained as follow:

2NaCl —> 2Na + Cl₂

From the balanced equation above,

2 moles of NaCl reacted to produce 1 mole of Cl₂.

Therefore, 4×10⁵ moles of NaCl will react to produce = (4×10⁵ × 1)/2 = 2×10⁵ moles of Cl₂.

Thus, 2×10⁵ moles of Cl₂ were obtained from the reaction.

Finally, we shall determine the volume of Cl₂ produced. This can be obtained as follow:

1 mole of Cl₂ at stp = 22.4 dm³

Therefore,

2×10⁵ moles of Cl₂ at stp = 2×10⁵ 22.4

2×10⁵ moles of Cl₂ at stp = 4.48×10⁶ dm³

Thus, the volume of chlorine obtained from the reaction is 4.48×10⁶ dm³

6 0

3 years ago

12.0 of .500 M NaOH neutralized 6.0 ml of HCl solution. What was the molarity of the HCl

frozen [14]

The molarity of the HCl is 1 M when 12.0 of .500 M NaOH neutralized 6.0 ml of HCl solution.

Explanation:

Data given:

molarity of the base NaOH, Mbase =0. 5 M

volume of the base NaOH, Vbase = 12 ml

volume of the acid, Vacid = 6 ml

molarity of the acid, Macid = ?

The titration formula for acid and base is given as:

Mbase Vbase = Macid Vacid

Macid = $\frac{0. 5 X 12}{6}$

Macid = 1 M

we can see that 1 M solution of HCl was used to neutralize the basic solution of NaOH. The volume of NaOH is 12 ml and volume of HCl used is 6ml.

8 0

3 years ago

(Based on q = -sm∆T)

vekshin1

Answer:

Sn < Brass ≈ Zn < Al

Step-by-step explanation:

Sn < Brass ≈ Zn < Al

C/J·°C⁻¹g⁻¹: .0.246 < 0.418 ≈ 0.419 < 0.734

3 0

3 years ago

What is the volume, in liters, of 2.00 moles of hydrogen at STP?

Ber [7]

The volume of one mole of any gas at STP is 22.4 L. So, at STP, the volume of 2.00 moles of hydrogen gas would be (22.4 L/mol)(2 mol H2) = 44.8 L.

8 0

3 years ago

When the equation Al + Br2 → AlBr3 is balanced, the coefficient for Br2 isSingle choice.

zheka24 [161]

Answer:

The answer should be 2 because to balance the equation you should have to change to equation to this; 2Al + 3Br2 => 2AlBr3, so that there is a total of 2 Aluminums and 6 Bromiums on either side of the equation.

Explanation:

7 0

3 years ago