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GREYUIT [131]
3 years ago
14

A cube has an edge lengths of 5 cm. A rectangular prism has dimensions of 5 cm, 25 cm, and 1 cm. Which of the following statemen

ts is incorrect?
A. The cube has a volume of 25 cm cubed.
B. The cube and rectangular prism have the same volume.
C. The volume of the rectangular prism is 125 cm cubed.
Mathematics
2 answers:
murzikaleks [220]3 years ago
6 0

The volume of cube and rectangular prism are same. Option B.

Step-by-step explanation:

Given,

The length of the edge of the cube (a) = 5 cm

The dimension of rectangular prism (l×b×h) = 5 cm×25 cm×1 cm

To find the relation between the volume of cube and rectangular prism.

Formula

The volume of a cube = a³ cube cm

The volume of rectangular prism = l×b×h cube cm

Now,

The volume of a cube = 5³ cube cm = 125 cube cm

The volume of rectangular prism = 5×25×1 cube cm = 125 cube cm

Hence,

The volume of cube and rectangular prism are same.

shepuryov [24]3 years ago
5 0

Answer:

Option A is the correct answer

Step-by-step explanation:

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4 years ago
A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. ​a) E
polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) \alpha =1-0.98=0.02

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq  p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and z_{\alpha/2} is the z-value that let a probability of \alpha/2 on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, \alpha by 0.02 and z_{\alpha/2} by 2.33

Where p' and \alpha are calculated as:

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So, replacing the values we get:

0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq  p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence 1-\alpha is equal to 98%

It means the the level of significance \alpha is:

\alpha =1-0.98=0.02

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