The density of an unknown crystal is 2.65 g/mol. What will the volume read if a 4.46 g sample is added to a graduated cylinder c ontaining 25.0 ml of water?
1 answer:
The density of crystal is 2.65 g / mL
we know that
Density = Mass / Volume
So volume occupied = Mass / density
Mass of crystal = 4.46 g
So volume occupied by crystal = 4.46 / 2.65 = 1.68 mL
As the graduated cylinder contains water upto 25.0 mL
So if we immerse the crystal in that cylinder the water level will rise to 25+1.68 = 26.68mL
so the new read will be 26. 68 mL
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