Answer:
pH = 13.1
Explanation:
Hello there!
In this case, according to the given information, we can set up the following equation:
Thus, since there is 1:1 mole ratio of HCl to KOH, we can find the reacting moles as follows:
Thus, since there are less moles of HCl, we calculate the remaining moles of KOH as follows:
And the resulting concentration of KOH and OH ions as this is a strong base:
And the resulting pH is:
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Explanation:
The chemical reaction equation will be as follows.
In this reaction, 1 mole of reacts with 3 mole NaOH. So, the number of moles of
present in 150 ml of 0.1 M solution is calculated as follows.
No. of moles =
= 0.015 mol
As it reacts with 3 moles of NaOH. Hence, no.. of moles of NaOH are:
= 0.045 mol
So, moles of NaOH in 400 of 0.2 M NaH is as follows.
No. of moles =
= 0.080 mol
Hence, no. of moles remained after the reaction are as follows.
(0.080 - 0.045) mol
= 0.035 mol NaOH in 550 ml (400 ml + 150 ml)
As molarity is the no. of moles present in liter of solution. Hence, molarity of NaOH is as follows.
Molarity =
=
= 0.0636 M
As, = 0.0636 M. Hence, pOH will be 1.20.
As, pH + pOH = 14
pH = 14 - pOH
= 14 - 1.20
= 12.80
Also,
So,
= M
Thus, we can conclude that pH of the given solution is 12.80 and its hydrogen ion concentration is M.