The enthalpy of formation for C6 H6 (I) is 49.0 kJ/mol. Consider the following reaction.
2 answers:
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1.04 ⨯ 10 M
<em>A</em> = <em>ε</em> by the Beer-Lambert law, where
- <em>A</em> the absorbance,
the path length,
- <em>ε</em> the molar absorptivity of the solute, and
concentration of the solution.
<em>A</em> and <em>ε </em>are the same for both solutions. Therefore, is constant;
is inversely proportional to
. The 100 mL sample would have a concentration 1/4.78 times that of the 45.0 mL reference.
The 13.0 mL standard solution has a concentration of 5.17 ⨯ M. Diluting it to 45.0 mL results in a concentration of
1.494 M.
is inversely related to
for the two solutions. As a result, c₂ =
3.126 M.
The 30.0 mL sample has to be diluted by 30.0 / 100.0 times to produce the 100.0 mL solution being tested. The 100.0 mL solution has a concentration of 3.126 M. Therefore, the 30.0 mL solution has a concentration of 1.04 ⨯
M.
Answer : The molecular formula of the compound is,
Explanation :
Molecular formula : It is the representation of substance by the symbols and it denotes the number of atoms of each element present in the compound.
Now count the number of carbon, hydrogen, nitrogen and oxygen atoms present in the given compound.
As we see that in the given compound, there are 8 atoms of carbon element, 3 atoms of oxygen element, 1 atom of nitrogen element, 9 atoms of hydrogen element.
Thus, the molecular formula of the compound will be