Answer:
b) $49
Step-by-step explanation:
The question here is not if Alexis can mow the lawn faster or slower than the person who hires (actually, the time that the person hired took to mow the lawn is irrelevant).
The important part is the time Alexis can save hiring someone:
- Alexis mow her lawn in 30 minutes.
- Alexis earns $100 an hour. Then 30 minutes of her time is worthy $50.
Then, paying $50 or less is a good choice for Alexis.
Therefore the answer is b) $49.
Ah hah ! You said in there "race AGAIN". Tell us something about how the first race turned out, and we may have some information we can use to answer with. Right now we got nuttn.
Answer:
x=71
Step-by-step explanation:
All exterior angles add up to 360
x+x-6+x+4+x+2+x+5=360
combine all the x's
5x-6+4+2+5=360
add all the numbers
5x+5=360
isolate 5x by cancelling out 5
5x+5-5=360-5
simplify
5x=355
isolate the variable
5x/5=355/5
simplify
x=71
Answer:
12 and -2
Step-by-step explanation:
12-2=10
12x-2=-24
I hope this helps!
Original position: P1=(0,0)
<span>You drive 30 miles due east in a half hour: x=+30 miles, t1=1/2 hour=0.5 hours
</span><span>Then, you turn left and drive 30 miles north in 1 hour: y=+30 miles, t2=1 hour
Rectangular coordinates of final position: P2=(x,y)→P2=(30,30)
Total time: t=t1+t2=0.5 hours+1 hour→t=1.5 hours
Average speed: S ave=d/t
Total distance: d=x+y=30 miles+30 miles→d=60 miles
S ave = 60 miles / (1.5 hours)
S ave = 40 miles/hour
Velocity is a vector, the magnitude of this vector is the magnitude of the vector of change of position dividing by the total time t
The vector of change of position: s=P1-P2=(30,30)-(0,0)=(30-0,30-0)→
s=(30,30)
Magnitude of vector s=sqrt[30^2+30^2]=sqrt[30^2*2]=sqrt[30^2]*sqrt(2)
Magnitude of vector s=30*sqrt(2) miles
Magnitude of velocity vector = Magnitud of vector s / t
Magnitude of velocity vector = [30*sqrt(2) miles] / (1.5 hours)
Magnitude of velocity vector = 20*sqrt(2) miles / hour
Magnitude of velocity vector=20*1.4142 miles / hour
Magnitude of velocity vector=28.284 miles/hour
Polar coordinates of your position=(r, theta)
r=Magnitude of vector s=30*sqrt(2) miles
theta=tan^(-1) (y/x) = tan^(-1) [(30 miles) / (30 miles)]
theta=tan^(-1) (1)→theta=45°=Pi/4 (Pi=3.1416)
Polar coordinates of your position: ( 30*sqrt(2) miles, 45°)
Polar coordinate of your position: ( 30*sqrt(2) miles, Pi/4 )
Answers:
Average speed: 40 miles / hour
Velocity: 20*sqrt(2) miles / hour = 28.284 miles / hour
Rectangular coordinates of your position = (30,30)
Polar coordinates of your position=(30*sqrt(2) miles,45°)
Polar coordinates of your position=(30*sqrt(2) miles,Pi/4)</span>
