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3 years ago

What is the weight of a 20kg stone?

Physics

2 answers:

worty [1.4K]3 years ago

5 0

Answer: w = 200N

Explanation:

w = mg

m = 20kg

g = 10m/s^ (approximately)

w = 20kg . 10m/s^

w = 200N

KengaRu [80]3 years ago

3 0

Answer:

$\Huge \boxed{\mathrm{200 \ N}}$

Explanation:

$\sf Weight \ (N)= mass \ (kg) \times acceleration \ of \ gravity \ (m/s^2)$

$W=mg$

The mass of the stone is 20 kg.

The acceleration of gravity is approximately 10 m/s².

$W=20 \times 10$

$W=200$

The weight of the object is 200 N.

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A particle is moving with velocity v(t) = t2 _ 9t + 18 with distance, s measured in meters, left or right of zero, and t measure

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t = 5 s

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If this atom has a balanced charge, how many protons would you expect to find in this atom

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Radiation from the Sun The intensity of the radiation from the Sun measured on Earth is 1360 W/m2 and frequency is f = 60 MHz. T

Zina [86]

a) Total power output: $3.845\cdot 10^{26} W$

b) The relative percentage change of power output is 1.67%

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Explanation:

The intensity of electromagnetic radiation is given by

$I=\frac{P}{A}$

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In this problem, we have

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The area to be considered is area of a sphere of radius

$r=1.5\cdot 10^{11} m$ (distance Earth-Sun)

Therefore

$A=4\pi r^2 = 4 \pi (1.5\cdot 10^{11})^2=2.8\cdot 10^{23}m^2$

And now, using the first equation, we can find the total power output of the Sun:

$P=IA=(1360)(2.8\cdot 10^{23})=3.845\cdot 10^{26} W$

The energy of the solar radiation is directly proportional to its frequency, given the relationship

$E=hf$

where E is the energy, h is the Planck's constant, f is the frequency.

Also, the power output of the Sun is directly proportional to the energy,

$P=\frac{E}{t}$

where t is the time.

This means that the power output is proportional to the frequency:

$P\propto f$

Here the frequency increases by 1 MHz: the original frequency was

$f_0 = 60 MHz$

so the relative percentage change in frequency is

$\frac{\Delta f}{f_0}\cdot 100 = \frac{1}{60}\cdot 100 =1.67\%$

And therefore, the power also increases by 1.67 %.

In this second case, we have to calculate the new power output of the Sun:

$P' = P + \frac{1.67}{100}P =1.167P=1.0167(3.845\cdot 10^{26})=3.910\cdot 10^{26} W$

Now we want to calculate the intensity of the radiation measured on Mars. Mars is 60% farther from the Sun than the Earth, so its distance from the Sun is

$r'=(1+0.60)r=1.60r=1.60(1.5\cdot 10^{11})=2.4\cdot 10^{11}m$

Now we can find the radiation intensity with the equation

$I=\frac{P}{A}$

Where the area is

$A=4\pi r'^2 = 4\pi(2.4\cdot 10^{11})^2=7.24\cdot 10^{23} m^2$

And substituting,

$I=\frac{3.910\cdot 10^{26}}{7.24\cdot 10^{23}}=540 W/m^2$

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2 years ago

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kozerog [31]

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3 years ago

You put a bottle of soft drink in a refrigerator and leave it until its temperature has dropped 12.0K .

Bingel [31]

Answer: a) - 437.8° F, b) - 261°c.

Explanation: a) the kelvin and Fahrenheit temperature scale are related by the formulae below.

5 (°F - 32) = 9 (k - 273)

Where °F = temperature in Fahrenheit and k = temperature in kelvin.

For question A, k = 12.0, by substituting to have the value for °F, we have

5(°F - 32) = 9 ( 12 - 273)

5(°F - 32) = 9(-261)

5(°F - 32) = - 2349

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°F - 32 = - 469.8

°F = - 469.8 + 32

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Question B

The centigrade and kelvin scale are related by the formulae below

°c = k - 273

Where °c = temperature in centigrade and k = temperature in kelvin =12

°c = 12 - 273

°c = - 261

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3 years ago

What is the weight of a 20kg stone?​

What is the weight of a 20kg stone?