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3 years ago

PLS HELP DUE IN 1 HOUR WILL GIVE BRAINLIEST THANKS AND 5 STARSSS!!!

Mathematics

1 answer:

Alenkinab [10]3 years ago

7 0

Step-by-step explanation:

-2x - 10 = 14x - 7

-10 + 7 = 14x +2x

-3 = 16x

-3/16 =x

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−2/3a+1/8−1/6a−3/4 PLEASE HELP

prohojiy [21]

Answer:

Evaluate:

- $\frac{5a}{6}$ - $\frac{5}{8}$

Factor:

$\frac{5(-4a-3}{24}$

Step-by-step explanation:

6 0

3 years ago

What is/are the classification of functions that has its inverse?

UNO [17]

Answer:

Invertible functions

Step-by-step explanation:

An inverse of a function is one that reverses the operation of the function such that the result of the function on a variable, is reversed back to the initial variable

Therefore, when we have the the result of the function, f on x as y given as follows;

f(x) = y

The inverse of the function, g on the result, y gives the initial variable, x as follows;

g(y) = x

Example of invertible functions includes;

f(x) = x²

An example of a non-invertible function includes;

f(x) = 2·x².

4 0

3 years ago

A manufacturing plant earned $80 per man-hour of labor when it opened. Each year, the plant earns an additional 5% per man-hour.

baherus [9]

A function that gives the amount that the plant earns per man-hour t years after it opens is $\mathrm{A}(\mathrm{t})=80 \times 1.05^{\mathrm{t}}$

<h3>Solution:</h3>

Given that

A manufacturing plant earned $80 per man-hour of labor when it opened.

Each year, the plant earns an additional 5% per man-hour.

Need to write a function that gives the amount A(t) that the plant earns per man-hour t years after it opens.

Amount earned by plant when it is opened = $80 per man-hour

As it is given that each year, the plants earns an additional of 5% per man hour

So Amount earned by plant after one year = $80 + 5% of $80 = 80 ( 1 + 0.05) = (80 x 1.05)

Amount earned by plant after two years is given as:

$=(80 \times 1.05)+5 \% \text { of }(80 \times 1.05)=(80 \times 1.05)(1.05)=80 \times 1.052$

Similarly Amount earned by plant after three years $=80 \times 1.05^{t}$

$\begin{array}{l}{\Rightarrow \text { Amount earned by plant after } t \text { years }=80 \times 1.05^{t}} \\\\ {\Rightarrow \text { Required function } \mathrm{A}(t)=80 \times 1.05^{t}}\end{array}$