<h2>QUESTION:- It is easier to lift the same load by using three pulley system than by using two-pulley system.</h2>
<h2>ANSWER:- IN CASE OF IDEAL PULLEY SYSTEM</h2>
<h2>REASON:- </h2>
Logic behind is lies behind the mechanical advantage of the provided bt the Pulley system.
as if we calculate the mechanical advantage of the 2 Pulley system we will have the value 2
And if we will calculate the mechanical advantage of the 3 pulley system then we will get the value of 3
so due to extra mechanical advantage we feel it easy to move with 3 pulley system then 2 Pulley system

In order to calculate the amount of energy required, we must first check the latent heat of vaporization of water from literature. The latent heat of vaporization of any substance is the amount of energy required per unit mass to convert that substance from a solid to a liquid. For water this is 2,260 J/g. We now use the formula:
Energy = mass * latent heat
Q = 50 * 2,260
Q = 113,000 J
113,000 Joules of heat energy are required.
We have the meats Arby’s we beat them kids
Answer:
1- For the track B. The potential energy is the same for the two cars, but because of the slope of the track, the car B earn kinetic energy faster. The gravitation acceleration of the cars will be g•sinθ, and the angle of the track B will have a bigger value for sinθ
2- The conservation of energy applies because the roller coaster is a closed track. When a car climb the track, it earn GPE, which is given by mgh, when it get down in the track, it transform GPE in KE, which is given in 1/2mv².
3-
Position of car (m) GPE KE GPE + KE
top (30m) 60000 0 60000
bottom (0m) 0 60000 60000
halfway down (15m) 30000 30000 60000
three-quarters way down 15000 45000 60000
Answer:
<em>Because </em><em>of </em><em>the </em><em>given </em><em>stranded</em><em> </em><em>wires </em><em>is </em><em>that </em><em>it's </em><em>thinner </em><em>there </em><em>are </em><em>even </em><em>more </em><em>air </em><em>gaps </em><em>and </em><em>a </em><em>greater </em><em>surface</em><em> </em><em>area </em><em>in </em><em>the </em><em>individual</em><em> </em><em>stranded</em><em> wires</em><em> </em><em>then </em><em>therefore </em><em>it </em><em>carries </em><em>less </em><em>current </em><em>than </em><em>similar </em><em>solid </em><em>wires </em><em>can </em><em>with</em><em> </em><em>each</em><em> </em><em>type </em><em>of </em><em>wire </em><em>,</em><em> insulations</em><em> </em><em>technologies </em><em>can </em><em>greatly</em><em> </em><em>assist </em><em> </em><em>in </em><em>reducing</em><em> </em><em>power </em><em>dissipation</em><em>.</em>