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Karolina [17]
3 years ago
5

Which statement best describes a true solution?

Chemistry
2 answers:
kari74 [83]3 years ago
6 0

Option C: a true solution will not separate in a centrifuge.

A solution is said to be a true solution if the solute particles form homogeneous mixture with the solvent. In a homogeneous mixture, the size of the particle of solute is less than 1 nm, can not be seen from naked ice. In such solutions, the solute particles completely dissolves in solvent in all proportions and cannot settle down at bottom if kept at rest for some time.

As complete dissolution of solute takes place, there is no cloudy appearance in the true solution also, once the solution is formed solute and solvent particles can not be separated with simple processes such as heating, boiling and centrifugation.

For example, solution of sugar and water, sugar particles completely dissolve in water to form homogeneous mixture or true solution.

Therefore, a true solution will not separate in a centrifuge.




Orlov [11]3 years ago
5 0

Answer: answer is C

Explanation:

Just took the test

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The electron configurations of two unknown elements x and y are shown. X: 1s2 2s2 2p6 Y: 1s2 2s2 2p6 3s2 3p6 Which statement is
SVETLANKA909090 [29]

Answer:

B) They will react because X and Y can share two pairs of electrons to become stable

Explanation:

The electron configurations of two elements x and y are given :

X: 1s2 2s2 2p6

Y: 1s2 2s2 2p6 3s2 3p6

The statement that is true for both the elements is that, they both will react as they both can share two pairs of electrons to become stable.

To become stable the outermost shell or p orbital should have 8 electrons, so element X  can gain 2 atoms to become stable.

Element Y can also react as it can also share two atoms to fulfill its 3p orbital and will stable.

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6 0
3 years ago
Calculate the solubility of mn(oh)2 in grams per liter when buffered at ph=7.0. assume that buffer capacity is not exhausted
Vanyuwa [196]
When PH + POH = 14 
∴ POH = 14 -7 = 7

when POH = -㏒[OH-]

          7    = -㏒ [OH-]
∴[OH-] = 10^-7

by using ICE table:

           Mn(OH)2(s) ⇄  Mn2+ (aq)  + 2OH-(aq)
initial                              0                     10^-7
change                           +X                      +2X
Equ                                 X                  (10^-7 + 2X)

when Ksp = [Mn2+][OH-]^2

when Ksp of Mn(OH)2 = 4.6 x 10^-14

by substitution:

4.6 x 10^-14 = X*(10^-7+2X)^2  by solving this equation for X

∴ X =2.3 x 10-5 M

∴ The solubility of Mn(OH)2 in grams per liter (when the molar mass of Mn(OH)2 = 88.953 g/mol
= 2.3 x10^-5 moles/L * 88.953 g/mol

= 0.002 g/ L
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