Answer:
Octane is a hydrocarbon and an alkane with the chemical formula C 8 H 18, and the condensed structural formula CH 3 (CH 2) 6 CH 3.Octane has many structural isomers that differ by the amount and location of branching in the carbon chain. One of these isomers, 2,2,4-trimethylpentane (commonly called iso-octane) is used as one of the standard values in the octane rating scale.
Chemical formula: C₈H₁₈
Molar mass: 114.232 g·mol−1
Melting point: −57.1 to −56.6 °C; −70.9 to −69.8 °F; 216.0 to 216.6 K
Solubility in water: 0.007 mg dm−3 (at 20 °C)
Since Qp>Kp , the reaction is not at equilibrium.
<h3>What is the equilibrium constant?</h3>
The equilibrium constant shows the extent to which reactants are converted into products.
Now we have to obtain the Qp as follows;
Qp =[CH3OH]/[CO] [H2]^2
Qp = 0.265/(0.265) (0.265)^2
Qp = 14.2
Now we know that Kp = 6.09×10−3, Since Qp>Kp , the reaction is not at equilibrium.
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Answer:
Identify the flaw in the way Maria set up her experiment.She did not take pictures.pictures.She She did did not not wait wait long long enough.enough.She She did did not not measure measure the the temperature.temperature.She She did did not not mix mix the the substances substances well well enough.enough.
your welcome :p
The energy released when electron move from n=4 to n=3 is 0.66 eV
We know that in an atom energy of nth state is
eV
where n is the energy level
Therefore,
Thus, 
= -0.85eV
= -1.51eV
Therefore, total mount of energy released in moving electron from n=4 to n=3 is given by -
= -0.85 - ( -1.51)
= 0.66eV
To know more about energy released in electron transition
brainly.com/question/8384785
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1/8=(1/2)^3 and the half life of radon is 3.8days
Half life is the time it takes for half of any amount of a radioactive substance to decay into something else.
Therefore for a sample of radon to decay to 1/8 of its original amount, it would take 3 x 3.8days=11.4 days
