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3 years ago

Polynomials is -y12+y15+y10-4y written in standard form?

1 answer:

8 0

Hi there!

To write the polynomials in standard form, we need to put the variables that has the highest exponent in front.

As you can see we have y^15 so it should be in front and so on...

Thus, the answer is

y^15 - y^12 + y^10 - 4y

I hope this helps and please let me know if you have questions about the answer.

Good luck with your study!

You might be interested in

Given that(4,6) is on the graph of f(x) find the corresponding point for the function f(-4x)

Len [333]

Answer:

(-1,6)

Step-by-step explanation:

Given that(4,6) is on the graph of f(x)

f(-4x) means x is multiplied by -4

When x is multiplied by -1 then there will be reflection over y axis

We multiply every point by -1. so multiply the x values of the given point (4,6) by -1

New point is (-4,6)

If any number is multiplied with x then there will be a horizontal compression or stretch.

4 is multiplied with x , so there will be horizontal compression because 4 is greater than 1

To get new point, we divide the x values by 4 for compression

we already got (-4,6) after multiplying by -1

Now we divide the x coordinate -4 by 4 = -1

So corresponding point for the function f(-4x) is (-1,6)

5 0

3 years ago

Which of the following options have the same value as 30\%30%30, percent of 818181?

Nataly_w [17]

Answer:

Option B is correct = $0.3 \times 81$

Step-by-step explanation:

The complete question is: Which of the following options have the same value as 30% of 81?

Group of choices is:

(A) $\frac{30}{100}\times 81 \times 100$

(B) $0.3 \times 81$

(D) $\frac{3}{10}\times 81 \times 10$

(E) $30 \times 81$

Now, the expression given to us is 30% of 81.

Simplifying the above expression we get;

30% of 81 = $\frac{30}{100} \times 81$

= $\frac{3}{10} \times 81$ = $0.3 \times 81$

Now, we will solve each of the given options and then see which option matches with our calculation.

Option (A) is given;

$\frac{30}{100}\times 81 \times 100$ = $30 \times 81$

This doesn't match with our answer, so this option is not correct.

Option (B) is given;

$0.3 \times 81$

This matches with our answer, so this option is correct.

Option (C) is given;

$0.03 \times 81$

This doesn't match with our answer, so this option is not correct.

Option (D) is given;

$\frac{3}{10}\times 81 \times 10$ = $3 \times 81$

This doesn't match with our answer, so this option is not correct.

Option (E) is given;

$30 \times 81$

This doesn't match with our answer, so this option is not correct.

6 0

4 years ago

What is HL??? HL=__ Image Below

Advocard [28]

Consider a trapezoid GJKF with:

GH=JH (hypothesis)

FL=KL (hypothesis)

so HL is the median of trapezoid GJKF

so: HL=1/2(2.5+1.2)=1.85

4 0

2 years ago

What value of y will make this expression equal to 2.45?

MA_775_DIABLO [31]

Any value of y, except when y = -4.9, will make the expression equal to 2.45.

5 0

3 years ago

Read 2 more answers

The mean preparation fee H&R Block charged retail customers in 2012 was $183 (The Wall Street Journal, March 7, 2012). Use t

astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

z(p)= $\frac{ME*\sqrt{N}}{s }$ where

Me is the margin of error from the mean

s is the standard deviation of the population

N is the sample size

z(p)= $\frac{8*\sqrt{30}}{50 }$ ≈ 0.8764

by looking z-table corresponding p value is 1-0.3808=0.6192

z(p)= $\frac{8*\sqrt{50}}{50 }$ ≈ 1.1314

by looking z-table corresponding p value is 1-0.2578=0.7422

z(p)= $\frac{8*\sqrt{100}}{50 }$ ≈ 1.6

by looking z-table corresponding p value is 1-0.1096=0.8904

Minimum required sample size for 0.95 probability is

N≥ $(\frac{z*s}{ME} )^2$ where

N is the sample size

z is the corresponding z-score in 95% probability (1.96)

s is the standard deviation (50)

ME is the margin of error (8)

then N≥ $(\frac{1.96*50}{8} )^2$ ≈150.6

Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

7 0

3 years ago