If 4=2^2
8=2^3
(2^)2x+10=(2^)6x
(2^)6x-(2^)2x=10
(2^)2x×7=10, where x has no real value
Answer:
C. 178−−−√ m
Step-by-step explanation:
Given the following :
v = final velocity (in m/s)
u = initial velocity (in m/s)
a = acceleration (in m/s²)
s = distance (in meters).
Find v when u is 8 m/s, a is 3 m/s², and s is 19 meters
Using the 3rd equation of motion :
v^2 = u^2 + 2as
v^2 = 8^2 + 2(3)(19)
v^2 = 64 + 114
v^2 = 178
Take the square root of both sides :
√v^2 = √178
v = √178
Option a is true and others are false
Answer:
<em>In the next year, Anthony worked 2,084 hours</em>
Step-by-step explanation:
Anthony worked 1,697 hours in 2010.
We also know Anthony worked 22.8% more hours than in 2010.
The problem requires to calculate how much did Anthony work in the next year.
It can be calculated as follows:
Take 22.8% of 1,697:

Now calculate by adding it to the original number of hours:
1,697 + 387 = 2,084 hours
In the next year, Anthony worked 2,084 hours
Answer:
D
Step-by-step explanation:
11 per 1,000