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4 years ago

C an somebody please tell me what 9+10 is?

1 answer:

5 0

' 9 + 10 ' is a simple exercise in addition. Its solution is 19 .

There is junk floating around the internet saying that 9+10=21.
That statement is false, and the arithmetic is wrong.
The whole thing is a joke. If you ask someone to prove it, they will
perform a demonstration with Roman numerals, but the way they handle
the Roman numerals is itself defective, and they're hoping you won't notice.

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Describe how (2^3) (2^-4) can be simplified

Usimov [2.4K]

Answer:

$2^{-7}$

Step-by-step explanation:

we have

$(2^{-3})(2^{-4})$

In this problem we know that the base remains the same and you will have to add the exponents to simplify.

$(2^{-3})(2^{-4})=2^{-3-4}$

$=2^{-7}$

3 0

4 years ago

Read 2 more answers

The Rocky Mountain News (January 24, 1994) indicated that the 20-year mean snowfall in the Denver/Boulder region is 28.76 inches

ycow [4]

Answer:

The p-value of the test is 0.0007 < 0.05, indicating that the the snowfall for the 1993-1994 winters was higher than the previous 20-year average.

Step-by-step explanation:

20-year mean snowfall in the Denver/Boulder region is 28.76 inches. Test if the snowfall for the 1993-1994 winters has higher than the previous 20-year average.

At the null hypothesis, we test if the average was the same, that is, of 28.76 inches. So

$H_0: \mu = 28.76$

At the alternate hypothesis, we test if the average incresaed, that is, it was higher than 28.76 inches. So

$H_1: \mu > 28.76$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

28.76 is tested at the null hypothesis:

This means that $\mu = 28.76$

Standard deviation of 7.5 inches. However, for the winter of 1993-1994, the average snowfall for a sample of 32 different locations was 33 inches.

This means that $\sigma = 7.5, X = 33, n = 32$ .

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{33 - 28.76}{\frac{7.5}{\sqrt{32}}}$

$z = 3.2$

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 33, which is 1 subtracted by the p-value of z = 3.2. In this question, we consider the standard level $\alpha = 0.05$ .

Looking at the z-table, z = 3.2 has a p-value of 0.9993.

1 - 0.9993 = 0.0007

The p-value of the test is 0.0007 < 0.05, indicating that the the snowfall for the 1993-1994 winters was higher than the previous 20-year average.

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3 years ago

These are two similar triangles.<br> What does x equal?

tangare [24]

Answer:

112

Step-by-step explanation:

So, we know that a triangle's sides must add up to have a sum of 180. If you add up your given lengths and you should get 47, not including x. Then if you look at the left side/the one without a given length and it should be identical to the 21, so you know that side is 21. So now add 21 to 47, you should get 68. Finally, you subtract 68 from 180 like this: 180-68, and it should equal 112. So you're answer is 112.

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3 years ago

Given that each unit on the map represents 5 miles, what is the actual distance from Oceanfront to Seaside?

KengaRu [80]

Answer:about 40 miles

Step-by-step explanation:

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3 years ago

What is 3 and 1/3 multiplied by 2 3/5

Setler79 [48]

The answer to the problem is 8 2/3.

Hope This Helps

7 0

4 years ago

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