Answer:
value if a =

Step-by-step explanation:
here's the solution :-
=》
![\frac{ 2(\sqrt{m}) {}^{3} }{ \sqrt[4]{m} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%202%28%5Csqrt%7Bm%7D%29%20%20%7B%7D%5E%7B3%7D%20%7D%7B%20%5Csqrt%5B4%5D%7Bm%7D%20%7D%20)
=》

=》

=》

=》

=》

so, a = 5/4
Answer:
6.57, 6.38, 6.125, 6.057, 6.03, 6.01
Answer:
After 22 seconds the projectile reach its maximum height of 4,840 units
Step-by-step explanation:
we have

This is a vertical parabola downward (because the leading coefficient is negative)
The vertex is a maximum
Find out the coordinates of the vertex
Convert the quadratic equation in vertex form
Factor -10

Complete the square


Rewrite as perfect squares

The vertex is the point (22,4,840)
therefore
After 22 seconds the projectile reach its maximum height of 4,840 units
The first one would be x^12
Answer: Example: 15 ÷ 5
Step-by-step explanation: