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vredina [299]
3 years ago
10

Formula for velocity

Physics
2 answers:
Sindrei [870]3 years ago
4 0
Distance divided by time
77julia77 [94]3 years ago
3 0

Hello there!

Velocity is a displacement of an object during a specific unit of time. Displacement per unit of time or displacement  divide by time.

Formula: V=Δx/t

Hope this helps!

Thank you for posting your question at here on Brainly.

-Charlie

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What is the relationship between an object’s temperature and its heat?
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Explanation:

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4 years ago
The 1.5-kg collar C starts from rest at A and slides with negligible friction on the fixed rod in the vertical plane. Determine
arlik [135]

Answer:

Explanation:

check attached image for figure, there is supposed to be a figure for this question containing a distance(height of collar at position A) but i will assume 0.2m or 200mm

Consider the energy equilibrium of the system

U_{A-B}=\bigtriangleup T\\\\F\cos 30°\times h_A - F\sin30°\times h_A + Wh_A=\frac{1}{2}m(v^2_B-v^2_A)\\\\v_B=\sqrt{\frac{2Fh_A(\cos 30° - \sin30°)+mgh_A}{m+v^2_A}}

Here, F is the force acting on the collar, h_A is the height of the collar at position A, m is the mass of the collar C, g is the acceleration due to gravity, v_B is the velocity of the collar at position B, and v_A is the velocity of the collar at A

Substitute 14.4N for F, 0.2m for h_A, 1.5kg for m, 9.81m/s^2 for g and 0 for v_A

v_B=\sqrt{\frac{2(14.4\times 0.2(\cos 30° - \sin30°)+1.5\times 9.81\times 0.2}{1.5+0}}\\\\=\sqrt{\frac{6.618}{1.5}}\\\\=4.412m/s

Therefore, the velocity at which the collar strikes the end B is 4.412m/s

8 0
3 years ago
If an object exerts a pressure of 16lb/in^2 and it has an area of 2 in^2 squared what is the weight of the object?
lesantik [10]

Answer:32Ib

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6 0
3 years ago
50. a kangaroo can jump over an object 2.50 m high. (a) calculate its vertical speed when it leaves the ground. (b) how long is
Ira Lisetskai [31]

Answer:

The easiest way to do this is to realize that the time to fall is the same as the rise time (conservation of energy can easily verify this)

S = 1/2 g t^2      time to fall 2.5 m

t = (5 / 9.8)^1.2 = .714 sec         time in air

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Check:

S = v t - 1/2 g t^2       where v is the initial vertical speed

S = 7 * .714 - 4.9 * .714^2 = 2.5 m        total vertical distance traveled

6 0
2 years ago
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