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S_A_V [24]
3 years ago
9

Iodine 131 half life is 8.0 days. Ten percent of the original sample o his isotope remains after (a) 22.7 days (b) 24.9 days (c)

26.6 days (d) 28.1 days
Physics
1 answer:
Artyom0805 [142]3 years ago
4 0

Answer:

option (c) is correct

Explanation:

Half life of a substance is the time in which the element becomes half of is initial value.

half life, T = 8 days

Amount remaining, N = 10 % of original value

Let the original value is No.

N = 10% of No

N = 0.1 No

Let the time taken is t and the decay constant is λ.

The relation between the decay constant and the half life is given by

\lambda =\frac{0.6931}{T}=\frac{0.6931}{8}=0.08664 per day

Us the equation of radioactivity

N=N_{0}e^{-\lambda t}

0.1N_{0}=N_{0}e^{-0.08664 t}

e^{0.08664 t}=10

Taking natural log on both the sides, we get

0.08664 t = 2.303

t = 26.6 days

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Two bodies are falling with negligible air resistance, side by side, above a horizontal plane. If one of the bodies is given an
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Answer:

Explanation:

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