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2 years ago

How do positive and negative acceleration differ?

Physics

2 answers:

horsena [70]2 years ago

6 0

Answer:

acceleration

Explanation:

acceleration determines whether you will be adding to or subtracting from the velocity. while negative acceleration means you will subtract from the current value of the velocity and a positive acceleration means you will add

patriot [66]2 years ago

6 0

ANSWER:

✔ Positive acceleration represents an object speeding up; negative acceleration represents an object slowing down.

NOTE: Negative acceleration is also called as Retar-dation.

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What is the difference between homophones and homographs.

Natali5045456 [20]

Answer:

*Homophones are words that sound the same but are different in meaning or spelling.

*Homographs are spelled the same, but differ in meaning or pronunciation.

Explanation:

8 0

2 years ago

What is the equivalent resistance of the circuit?

Ivanshal [37]

Answer:

Since the wire is not splitting at any point in the circuit,

the resistors are in series

Hence, Equivalent resistance = 10 + 20 + 30

Equivalent Resistance = 60 Ω

8 0

2 years ago

If object a has more mass than object b does object a contain more matter?

aev [14]

The answer should be a yes

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3 years ago

A square sheet of rubber has sides that are 20 cm long. What is the area of the square of rubber in cm squared?

Alinara [238K]

Answer:

400cm^2

Explanation:

sides are 20cm long Area for a square is a squared

since all the lides are of equal length you can just choose one side.

20squared is 400

20 x 20 = 400cm squared

Hope this helps :)

6 0

3 years ago

Projectile's horizontal range on level ground is R=v20sin2θ/g. At what launch angle or angles will the projectile land at half o

seraphim [82]

Answer:

$\theta = 15^o \: or\: 75^o$

Explanation:

As we know that the formula of range is given as

$R = \frac{v^2sin2\theta}{g}$

now we know that

maximum value of the range of the projectile is given as

$R_{max} = \frac{v^2}{g}$

now we need to find such angles for which the range is half the maximum value

so we will have

$\frac{R}{2} = \frac{v^2}{2g} = \frac{v^2sin(2\theta)}{g}$

$sin(2\theta) = \frac{1}{2}$

$2\theta = 30 or 150$

$\theta = 15^o \: or\: 75^o$

7 0

3 years ago