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Luba_88 [7]
3 years ago
5

How do positive and negative acceleration differ?

Physics
2 answers:
horsena [70]3 years ago
6 0

Answer:

acceleration

Explanation:

acceleration determines whether you will be adding to or subtracting from the velocity. while negative acceleration means you will subtract from the current value of the velocity and a positive acceleration means you will add

patriot [66]3 years ago
6 0

ANSWER:

✔ Positive acceleration represents an object speeding up; negative acceleration represents an object slowing down.

NOTE: Negative acceleration is also called as Retar-dation.

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A spring has a relaxed length of 35 cm (0.35 m) and its spring stiffness is 12 N/m. You glue a 66 gram block (0.066 kg) to the t
Sonbull [250]

We have that the value for y is

y=0.12376m

 

From the Question we are told that

Relaxed length of 35 cm (0.35 m)

Spring stiffness is 12 N/m.

Glue a 66 gram block (0.066 kg)

Total length is l_t=16 cm

Block during a 0.24-second interval

Generally the equation for the Force of spring of block  is mathematically given as

F_{spring}=kx\\\\\ F_{spring}=12*(0.35-0.16)\\\\ F_{spring}=2.28N

Generally

F_{elastic}=-mg\\\\F_{elastic}=-0.066*9.8\\\\F_{elastic}=-0.6468N

Generally,Net Force

F_{net}=F_{spring}-F_{elastic}\\\\F_{net}=2.28N-(-0.6468N)\\\\F_{net}=2.9268N

Generally,Velocity of block

V_y=\frac{py}{m}

Where

Py= F_{net}*dt\\\\Py= 2.9268*0.08\\\\Py=0.234144

Therefore

V_y=\frac{0.234144}{0.066}\\\\V_y=3.547m/s

Generally the equation for the Velocity of block   is mathematically given as

Vy=\frac{yf-yt}{t-t_0}\\\\y=(3.547(0.08-0))-0.16

y=0.12376m

For more information on this visit

brainly.com/question/22271063?referrer=searchResults

4 0
3 years ago
If light of wavelength 700 nm strikes such a photocathode, what will be the maximum kinetic energy, in eV , of the emitted elect
Oksana_A [137]

If the light of wavelength 700 nm strikes such a photocathode the maximum kinetic energy, in eV, of the emitted electrons is 0.558 eV.

so - $KE_{max} = hc/lembda}  work

threshold when KE = 0

hc/lambda = work = 1240/900=1.38 eV

b) Kemax = hc/lambda - work = 1240/640 -1.38=0.558 eV

What is photocathode?

  • A photocathode electrolyte interface can be used in a photoelectrolysis cell as the primary light-harvesting junction (in conjunction with an appropriate electrochemical anode) or as an optically complementary photoactive half-cell in a tandem photoelectrode photoelectrolysis cell (Hamnett, 1982; Kocha et al, 1994).
  • In the case of the former, the electrode should ideally harvest photon energy across the majority of the solar spectrum in order to achieve the highest energy conversion efficiency possible.
  • In the latter case, however, the photocathode may only be active in a specific band of the solar spectrum in order to generate a cathodic photocurrent sufficient to match the current generated in the photoanodic half-cell.

To learn more about Photocathode from the given link:

brainly.com/question/9861585

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3 0
2 years ago
A. while<br>to rest<br>coming<br>down from a slide<br>you stop and come​
Pani-rosa [81]
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3 years ago
A car accelerates at a rate of 3 m/s^2. If its original speed is 8 m/s, how many seconds will it take the car to reach a final s
kkurt [141]

Answer:

\Large \boxed{\mathrm{5.67 \ seconds }}

Explanation:

\displaystyle \mathrm{acceleration \ = \ \frac{final \ velocity - initial \ velocity }{elapsed \ time}}

\displaystyle A \ = \ \frac{V_f - V_i }{t}

\displaystyle 3 \ = \ \frac{25 - 8 }{t}

\displaystyle 3 \ = \ \frac{17 }{t}

\displaystyle t \ = \ \frac{17 }{3} \approx 5.67

4 0
3 years ago
Excited hydrogen atoms radiate energy in the _________
sveticcg [70]

Answer:

infrared, visible and ultraviolet regions.

Explanation:

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