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netineya [11]
3 years ago
5

Element

Chemistry
1 answer:
Svetllana [295]3 years ago
7 0

Answer:

Number of moles = 10.6 mol

Explanation:

Given data:

Molar mass of H = 1.008 g/mol

Molar mass of C = 12.01 g/mol

Molar mass of O = 16.00 g/mol

Mass of citric acid = 2.03 kg (2.03×1000 = 2030 g)

Number of moles of citric acid = ?

Solution:

Formula:

Number of moles = mass/molar mass

Now we will calculate the molar mass of citric acid:

C₆H₈O₇ = (12.01× 6) + (1.008×8) + (16.00×7)

C₆H₈O₇ = 72.06 + 8.064+112

C₆H₈O₇ = 192.124g/mol

Number of moles = 2030 g/ 192.124g/mol

Number of moles = 10.6 mol

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The mass percent of element X
WINSTONCH [101]

Answer:

128.4 g

Explanation:

Step 1: Given data

  • Mass percent of element X in X(NO₃)₂: 52.55%
  • Mass of the element X in the sample: 67.50 g

Step 2: Determine the total mass of the sample

The mass percent of element X in X(NO₃)₂ is 52.55%, that is, there are 52.55 g of X every 100 g of X(NO₃)₂. Then, the mass of X(NO₃)₂ that contains 67.50 g of X is:

67.50 g X × 100 g X(NO₃)₂/52.55 g X = 128.4 g X(NO₃)₂

7 0
3 years ago
One of the waste byproducts of a nuclear reactor using uranium-235 is strontium-90 with half-life of about 28 years. If we have
e-lub [12.9K]

Answer:

(a) 140 years

(b) 3.125 pounds

Explanation:

<u>QuestIons</u>

(a) How long is five half-life

(b)  How much radioactive strontium is left after five half-life

Given that:

Half-life is about 28 years; &

There are 100 pounds of this radioactive waste

Five half-life will be;

= 28 × 5

= 140 years

The amount of radioactive remaining after five half-life is:

= 100 \times( \dfrac{1}{2}) ^5

= 100 × 0.03125

= 3.125 pounds

5 0
3 years ago
What is the difference between two atoms of carbon having the same number of neutrons?
Temka [501]
B. number of protons

3 0
3 years ago
Read 2 more answers
What effect does the addition of a catalyst have on a chemical reaction at equilibrium?
svetlana [45]

Answer:

C

Explanation:

In the presence of a catalyst, both the forward and reverse reaction rates will speed up equally. :)

7 0
3 years ago
A 0.245-L flask contains 0.467 mol co2 at 159 °c. Caculate the pressure using Van der Walls equation
AlladinOne [14]

Answer:

The right answer is "60.56 atm".

Explanation:

As we know,

Vander wall's equation is:

⇒ (P+\frac{n^2 a}{v^2} )(v-nb)=nRT

or,

⇒ P=\frac{nRT}{(v-nb)}-\frac{n^2 a}{v^2}

Here,

a = 3.59 L² atm mol⁻²

b = 0.0427 L mol⁻¹

By putting the values in the above equation, we get

⇒ P=\frac{0.467\times 0.0821\times 432}{0.245-0.467\times 0.0427}

       =\frac{(0.467)^2\times 3.49}{(0.245)^2}

       =73.61-13.05

       =60.56 \ atm

8 0
3 years ago
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