Answer:
IO₂
Explanation:
We have been given the mass percentages of the elements that makes up the compound:
Mass percentage given are:
Iodine = 79.86%
Oxygen = 20.14%
To calculate the empirical formula which is the simplest formula of the compound, we follow these steps:
> Express the mass percentages as the mass of the elements of the compound.
> Find the number of moles by dividing through by the atomic masses
> Divide by the smallest and either approximate to nearest whole number or multiply through by a factor.
> The ratio is the empirical formula of the compound.
Solution:
I O
% of elements 79.86 20.14
Mass (in g) 79.86 20.14
Moles(divide by
Atomic mass) 79.86/127 20.14/16
Moles 0.634 1.259
Dividing by
Smallest 0.634/0.634 1.259/0.634
1 2
The empirical formula is IO₂
95.611 g/mol that's the answers
That number has 6 significant numbers. It's precision would be 602.
Hope it helped.
Because zinc is above lead on the activity series. This means that in a single displacement reaction such as this one, Pb will not easily displace Zn.
According to your equation, for every mole of iron oxide (Fe2O3), it takes 3 moles of carbon monoxide (CO). So for 1.75 moles, it takes 3 times as many moles of CO.
1.75 x 3 = 5.25 moles of CO.
I think your product is CO2. Dalton's Law sayeth that the coefficients tell us the ratios of moles. So if you hve 1.75 moles of Fe(III)oxide, 3*1.75 moles of CO are needed (in theory) to react completely. The answer is requested in moles, so you need go no further.
