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Nata [24]
3 years ago
7

How many grams of o2 are consumed to precipitate all of the iron in 55.0 ml of 0.0350 m fe(ii)?

Chemistry
1 answer:
spayn [35]3 years ago
7 0
<span>Rust forms when 2 atoms of fe reacts with oxygen to form iron oxide as follows. 4Fe2 + 302 ==[]::::::::::::::::> 2Fe2O3. So basically 4 atoms of oxygen reacts with 3 atoms of oxygen to produce the product. We need to find the number of moles of Fe that reacts with Oxygen. Number of moles is the concentration of iron multiplied by the molarity. So we have 55 * 0.035 = 1.925 moles. Hence 1.925*4 atoms of iron which gives 7.7 moles will actually react with 3 *1.925 = 5.775 of Oxygen Since we know the number of moles of oxygen we can solve for its mass. No of moles = mass/molar mass. Mass = no of moles * molar mass = 5.775 * 32 = 184.5</span>
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Copper(II) nitrate forms a series of hydrates with the formula Cu(NO3)2.xH2O. These hydrates decompose to form copper(II) oxide.
maria [59]

Answer:

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2 years ago
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3 years ago
Help me please!! Is for my finals!!
BabaBlast [244]

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3 0
2 years ago
Calculate the mass of 1 molecule of water and 100 molecules of glucose​
lesya692 [45]

Explanation:

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Mass of 100 molecules of glucose = 180×100 =18000

3 0
2 years ago
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