Using the method of Lagrange multipliers, we have the Lagrangian

with partial derivatives (set equal to 0)





From

and

, we find that

. Then substituting into

, we find

and substituting these into

, we get

So we have two possible critical points,

, which give extreme values of

and

, respectively.
Answer:
wait what, what grade are u even in?? I barely understand this I'm in freaking 8th grade this is high school!
<span>x+yi = <span>8/(<span>4+8i)</span></span></span><span>x+yi = <span>2/(<span>1+2i)</span></span></span><span>x+yi = <span>2/(<span>1+2i) </span></span>× (<span><span>1−2i)/(</span><span>1−2i)</span></span></span><span>x+yi = (<span><span>2−4i) /</span>5</span></span><span><span>x+yi = <span>2/5</span>−<span>4/5</span>i
x= 2/5
y= -4/5i
</span></span>
Answer:
13
Step-by-step explanation:
in 8 hrs she can make 12 then cn only make one more so