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PIT_PIT [208]
1 year ago
10

What is the card balance

Mathematics
1 answer:
GaryK [48]1 year ago
8 0

Answer:

A card balance is the total amount of money that you currently owe on your credit card. The balance increases when purchases are made and decreases when payments are made. Purchases, balance transfers, foreign exchange, fees, and interest all factor into your credit card balance.

please brainlest and like

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The symbol ⊕ is used to denote exclusive or, so p ⊕ q ≡ (p v q) ^ ~ (p ^ q).
Elan Coil [88]

I'll use text forms of the logical symbols because copying/pasting on mobile is annoying.

⊕ = XOR

∨ = OR

∧ = AND

~ = NOT

↔ = IFF (meaning "if and only if")

→ = IMP (short for "implies")

and for logical equivalence I'll use a regular equal sign.

Then

p XOR q = (p OR q) AND NOT (p AND q)

(a) By definition of XOR, we have

p XOR p = (p OR p) AND NOT (p AND p)

= p AND NOT p

and this is tautologically FALSE.

(b) To rewrite XOR, first distribute the NOT over the AND using DeMorgan's law:

NOT (p AND q) = NOT p OR NOT q

Then we can interchange the AND and ORs using their respective distributive properties. That is,

p XOR q = (p OR q) AND (NOT p OR NOT q)

= (p AND (NOT p OR NOT q)) OR (q AND (NOT p OR NOT q))

= ((p AND NOT p) OR (p AND NOT q)) OR ((q AND NOT p) OR (q AND NOT q))

Both (p AND NOT p) and (q AND NOT q) are tautologically FALSE, so the truth value of either OR depends only on the other statements, so we have

p XOR q = (p AND NOT q) OR (q AND NOT p)

Recall the definition of IFF:

p IFF q = (p IMP q) AND (q IMP p)

Also recall that IMP is logically equivalent to

p IMP q = p OR NOT q

Then we have

p IFF q = (p OR NOT q) AND (q OR NOT p)

so that its negation is

NOT (p IFF q) = NOT ((p OR NOT q) AND (q OR NOT p))

= NOT (p OR NOT q) OR NOT (q OR NOT p)

= (NOT p AND q) OR (NOT q AND p)

The statements in bold match, so p XOR q is indeed equivalent to NOT (p IFF q).

3 0
2 years ago
The number of hours, t, it takes a boat to travel 15 miles upstream is represented
iogann1982 [59]

The equation of c is an illustration of subject of formula

The equation of c in terms of r and t is c = r - 15/t

<h3>How to determine the equation?</h3>

The equation is given as:

t = 15/(r - c)

Cross multiply

t(r - c) = 15

Divide both sides by t

r - c = 15/t

Subtract r from both sides

-c = -r + 15/t

Multiply both sides by -1

c = r - 15/t

Take LCM

c = \frac{rt - 15}{t}

Hence, the equation of c in terms of r and t is c = \frac{rt - 15}{t}

Read more about subject of formula at:

brainly.com/question/10643782

8 0
1 year ago
The multipliers of this system of equations have been determined to create opposite terms of the y-variable.
sergiy2304 [10]

Answer:

-48

Step-by-step explanation:

i think im sorry if im wrong

5 0
3 years ago
Write the equation of the line that passes through the points (-6,-1) and (-4,2). Put your answer in fully simplified point-slop
Archy [21]

(\stackrel{x_1}{-6}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{-4}-\underset{x_1}{(-6)}}} \implies \cfrac{2 +1}{-4 +6} \implies \cfrac{ 3 }{ 2 }

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{\cfrac{3}{2}}(x-\stackrel{x_1}{(-6)}) \implies {\large \begin{array}{llll} y +1= \cfrac{3}{2} (x +6) \end{array}}

4 0
1 year ago
X - 11 / 3 = - 4 / 5 x + 5 / 6
arsen [322]

Answer:

SOLVE FOR X

x=2

Step-by-step explanation:

3 0
3 years ago
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