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dedylja [7]
3 years ago
13

Select the correct answer.

Mathematics
1 answer:
Marysya12 [62]3 years ago
3 0
Your answer will be A because the absolute value of -7 is 7 that is smaller than 8 8 smaller than 9 and -10 absolute value is 10 so A displayed in the right number sequence
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Five-card poker hand is dealt at random from a standard 52-card deck.
Alisiya [41]

Answer:

Step-by-step explanation:

a) The probability that the hand contains exactly one ace

No of ways of selecting one ace and four non ace would be

=4C1 (48C4)\\\\= 778320

i.e. α=778320

b) the probability that the hand is a flush

No of ways of getting a flush is either all 5 hearts or clubs of spades or dice

= 4(13C5) = 5148

ie. β=5148

c)  the probability that the hand is a straight flush

In each of the suit to get a straight flush we must have either A,2,3,4,5 or 2,3,4,5,6, or .... or 9,10, J, q, K

So total no of ways = =9(13C5) 4\\= 46332

γ=46332

5 0
3 years ago
Choose the correct equation for the line shown on the graph?
fomenos

<u>Answer:</u>

y=-1/4x-1

<u>How to find the </u><u>slope</u>

To find the slope of the line you need to do the change in y/change in x. This is also known as the rise/run. To do this you count the spaces in between the two points.

In this graph the change in y (rise) is 2. The change in x (run) is 8. Since the line is going down they are negative. The rise/run is -2/8. This can be simplified to -1/4.

Slope: -1/4x

<u>How to find the y-intercept</u>

To find the y-intercept, you need to look at where the line crosses y.

In this graph the line crosses y at -1.

Y-intercept: -1

<u>Final</u><u> </u><u>equation</u><u>:</u><u> </u><u>-</u><u>1</u><u>/</u><u>4x-1</u>

3 0
2 years ago
Solve 5.4p+13.1=−2.6p+3.5 . Check your solution.<br><br><br><br> p= __
maxonik [38]

5.4p +13.1 = −2.6p+3.5 .

5.4p + 2.6p = 3.5 -13.1

8.0p = -9.6

p = -9.6 / 8

p = -1.2

3 0
2 years ago
A random sample of 25 ACME employees showed the average number of vacation days taken during the year is 18.3 days with a standa
Norma-Jean [14]

Answer:

a) Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

b) df=n-1=25-1=24  

For this case the p value is given p_v = 0.0392

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 5% of signficance.  

c) Type I error, also known as a “false positive” is the error of rejecting a null  hypothesis when it is actually true. Can be interpreted as the error of no reject an  alternative hypothesis when the results can be  attributed not to the reality.

So for this case a type I of error would be reject the hypothesis that the true mean is less or equal than 15 and is actually true.

Step-by-step explanation:

Data given and notation  

\bar X=18.3 represent the sample mean

s=3.72 represent the sample standard deviation

n=25 sample size  

\mu_o =15 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a: State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean for vacation days is higher than 15, the system of hypothesis would be:  

Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part b: P-value  and conclusion

The first step is calculate the degrees of freedom, on this case:  

df=n-1=25-1=24  

For this case the p value is given p_v = 0.0392

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 5% of signficance.  

Part c

Type I error, also known as a “false positive” is the error of rejecting a null  hypothesis when it is actually true. Can be interpreted as the error of no reject an  alternative hypothesis when the results can be  attributed not to the reality.

So for this case a type I of error would be reject the hypothesis that the true mean is less or equal than 15 and is actually true.

3 0
2 years ago
I am confused please help
klemol [59]

Answer:

volume = lenght x width x height

v= 12x20x14

v=3,360 in³

3 0
2 years ago
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