6/11+1/2 what is the answer
1 answer:
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Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, is equal to
, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, . Since a and b were generic elements of H, then H/G is abelian.
Option C
<em><u>Solution:</u></em>
We have to solve for "x"
From given,
Solve for brackets
Use distributive property
a(b + c) = ab + ac
Therefore,
Combine the constants
Move the variables to left side of equation
Combine the like terms
Thus option C is correct