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3 years ago

Help with with 6x + 11 = -31

Mathematics

2 answers:

Oksi-84 [34.3K]3 years ago

8 0

So first you would cancel out the 11 on both sides so -31-11 =-42 The divide it by 6 -42 divided by 6 is -7

Lynna [10]3 years ago

7 0

Answer:

x=-7

Step-by-step explanation:

-31-11=-42 -42/6=-7

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the capacity of a school swimming pool is 243m cubed. An olympic pool is 50 m long, 25 m wide and 2 m deep, How much greater is

sveticcg [70]

Answer:

2257m3

Step-by-step explanation:

50x25x2=2500

2500-243=2257

6 0

2 years ago

PLEASE HELP!!!

AlekseyPX

Answer:

Step-by-step explanation:

Find the average rate of change of each given function over the interval [-2, 2]]:

✔️ Average rate of change of m(x) over [-2, 2]:

Average rate of change = $\frac{m(b) - m(a)}{b - a}$

Where,

a = -2, m(a) = -12

b = 2, m(b) = 4

Plug in the values into the equation

Average rate of change = $\frac{4 - (-12)}{2 - (-2)}$

= $\frac{16}{4}$

Average rate of change = 4

✔️ Average rate of change of n(x) over [-2, 2]:

Average rate of change = $\frac{n(b) - n(a)}{b - a}$

Where,

a = -2, n(a) = -6

b = 2, n(b) = 6

Plug in the values into the equation

Average rate of change = $\frac{6 - (-6)}{2 - (-2)}$

= $\frac{12}{4}$

Average rate of change = 3

✔️ Average rate of change of q(x) over [-2, 2]:

Average rate of change = $\frac{q(b) - q(a)}{b - a}$

Where,

a = -2, q(a) = -4

b = 2, q(b) = -12

Plug in the values into the equation

Average rate of change = $\frac{-12 - (-4)}{2 - (-2)}$

= $\frac{-8}{4}$

Average rate of change = -2

✔️ Average rate of change of p(x) over [-2, 2]:

Average rate of change = $\frac{p(b) - p(a)}{b - a}$

Where,

a = -2, p(a) = 12

b = 2, p(b) = -4

Plug in the values into the equation

Average rate of change = $\frac{-4 - 12}{2 - (-2)}$

= $\frac{-16}{4}$

Average rate of change = -4

The answer is D. Only p(x) has an average rate of change of -4 over [-2, 2]

3 0

3 years ago

2/5gal fill up 3/4 of a tank how many gallons will it take

Olin [163]

Answer:

8/15 gallons or 0.5333 gallons

Step-by-step explanation:

x = total

0.4 = 0.75x

0.4/0.75 = x

0.533 = x

0.533 = 8/15

5 0

2 years ago

Find the diameter of the object.

Anni [7]

Answer:

1 $\frac{1}{5}$ centimeters

Step-by-step explanation:

The diameter is equal to the radius × 2. We know that the radius is equal to 3/5 centimeters.

To solve this you must do $\frac{3}{5}$ × 2.

This equals $\frac{6}{5}$ , or 1 $\frac{1}{5}$ cm.

5 0

3 years ago

Simplify the expression. tan(sin^−1 x)

Blizzard [7]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2799412

_______________

Let $\mathsf{\theta=sin^{-1}(x)\qquad\qquad-\dfrac{\pi}{2}\ \textless \ \theta\ \textless \ \dfrac{\pi}{2}.}$

(that is the range of the inverse sine function).

So,

$\mathsf{sin\,\theta=sin\!\left[sin^{-1}(x)\right]}\\\\ \mathsf{sin\,\theta=x\qquad\quad(i)}$

Square both sides:

$\mathsf{sin^2\,\theta=x^2\qquad\qquad(but~sin^2\,\theta=1-cos^2\,\theta)}\\\\ \mathsf{1-cos^2\,\theta=x^2}\\\\ \mathsf{1-x^2=cos^2\,\theta}\\\\ \mathsf{cos^2\,\theta=1-x^2}$

Since $\mathsf{-\,\dfrac{\pi}{2}\ \textless \ \theta\ \textless \ \dfrac{\pi}{2},}$ then $\mathsf{cos\,\theta}$ is positive. So take the positive square root and you get

$\mathsf{cos\,\theta=\sqrt{1-x^2}\qquad\quad(ii)}$

Then,

$\mathsf{tan\,\theta=\dfrac{sin\,\theta}{cos\,\theta}}\\\\\\ \mathsf{tan\,\theta=\dfrac{x}{\sqrt{1-x^2}}}\\\\\\\\ \therefore~~\mathsf{tan\!\left[sin^{-1}(x)\right]=\dfrac{x}{\sqrt{1-x^2}}\qquad\qquad -1\ \textless \ x\ \textless \ 1.}$

I hope this helps. =)

Tags: <em>inverse trigonometric function sin tan arcsin trigonometry</em>

3 0

3 years ago

Read 2 more answers