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olya-2409 [2.1K]
3 years ago
5

5+5 +3+3+4+4+5+5+&+&+7+7+8+8+9+9

Mathematics
1 answer:
worty [1.4K]3 years ago
8 0

Answer: 82

Step-by-step explanation: 5+5 +3+3+4+4+5+5+7+7+8+8+9+9

                                                10+6+8+10+14+16+18

                                                  16+18+30+18

                                                    34+48

                                                        82

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If a triangle has side lengths 7, 10, and 12, is it a right triangle??
Vesnalui [34]

Answer:

No. Remember, a right angle must have a 90 degree angle. We can find the lengths with the Pythagorean Theorem.

Step-by-step explanation:

Given the length 7, 10, and 12, we can assume that 12 is the hypotenuse (it is the longest length).

- we can use 7 and 10 interchangeably.

Fill in the equation, a^2 + b^2 = c^2

                 where c = 12, and a or b = 7 or 10.

To indicate if the given lengths would form a right angle, we can only input 7 or 10, not both.

Therefore, 7^2 + b^2 = 12^2 or 10^2 + b^2 = 12^2

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b= 9.7, not 10.

10^2 + b^2 = 12^2 ==> 100 + b^2 = 144 ==> <u>b = </u>\sqrt{44<u> ==> </u><u>6.633 </u>

b= 6.6, not 7.

Therefore, the lengths 7, 10, and 12, does NOT make a right triangle.

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Two is eight less than twice a number. What is the number?
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Step-by-step explanation:

First, break it down:

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GEOMETRY PROOFS!
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From the triangles , ∆REC and ∆RAC

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angle CRE = angle CRA (Given)

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∆REC =~ ∆RAC by SAS Property

⇛CE = CA (Congruent parts in a congruent triangles)

Hence , Proved

<em>Additional comment:-</em>

SAS property:-

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