The statement "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g" is FALSE.
Domain is the values of x in the function represented by y=f(x), for which y exists.
THe given statement is "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g".
Now we assume the
and 
So here since g(x) is a polynomial function so it exists for all real x.
<em> </em>does not exists when
, so the domain of f(x) is given by all real x except 6.
Now,

So now (fg)(x) does not exists when x=4, the domain of (fg)(x) consists of all real value of x except 4.
But domain of both f(x) and g(x) consists of the value x=4.
Hence the statement is not TRUE universarily.
Thus the given statement about the composition of function is FALSE.
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Answer:
1. Degree= 6, trinomial
2. degree= 4, binomial
Step-by-step explanation:
1. The largest exponent is 6 making it the degree and there are three terms because (m^5n^2), (mn^2), (n^6).
2. Since (9a^2bc^2) has the more than 1 exponent, you add them and the degree is 4. There are two terms because (2a^3b), (9a^2bc^2).
Answer:
B
Step-by-step explanation:
because when you replace x and y
you find 4=4
I thinks it’s C I maybe be wrong but it’s at least an answer