I will teach you the procedure and make a calculation, based on a hypothetical dimension.
Call x the length of the side.
You will obtaind two equilateral triangles from a square if you cut by the diagonal.
The length of the diagonal is x√2.
If the sign is placed with the diagonal as the base and the vertex up (this is the righ angle), then the heigth is half the diagonal, i.e. (x√2) / 2.
So, if the side of the square is 100 inches, the diagonal is 100√2 and half diagonal is 50√2, which to the nearest tenth is 70,7 in.
Answer:
3x^2 -2x + 1 =3(x^2-2/3x+1/3)=3(x-1/3)^2+2/9*3= 3(x-1/3)^2+2/3
(x-1/3)^2 is greater or equal to zero
3(x-1/3)^2 is greater or equal to zero
and 2/3 is greater than zero
So there sum is greater than zero
Proved
Step-by-step explanation:
3x^2 -2x + 1 =3(x^2-2/3x+1/3)
Consider x^2-2/3x+1/3
Remember that (a-b)^2 =a^2-2ab+b^2
x^2=a^2
a=x
-2/3x= -2*x*b
b=1/3
S0 (x-1/3)^2= x^2-2/3x+1/9
x^2-2/3x+1/3= x^2-2/3x+1/9+1/3-1/9= (x-1/3)^2+2/9
3x^2 -2x + 1 =3(x^2-2/3x+1/3)=3(x-1/3)^2+2/9*3= 3(x-1/3)^2+2/3
(x-1/3)^2 is greater or equal to zero
3(x-1/3)^2 is greater or equal to zero
and 2/3 is greater than zero
So there sum is greater than zero
Proved
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Add sides 1
Subtract sides 4z
Divide sides by 6
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Subtract sides y
Divide sides by 2
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Thus the correct answer is :
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1)A
2)B
If the dot it is filled it is equal or greater than whatever it is
If the dot is empty it means it is what ever the sign is and it doesn't equal to