Multiply. (2−5i)(3+i) Enter your answer, in standard form, in the box.

Mathematics

2 answers:

kykrilka [37]3 years ago

7 0

11-13i ............................

kifflom [539]3 years ago

4 0

2*3=6

2*i =2i

3*-5i=-15i

and -5i*i=-5i^2 i^2=-1 so you actually have 5

5-15i+2i+6 simplifies to 11-13i

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Gnoma [55]

Answer:

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Step-by-step explanation:

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Alborosie

Answer:

H 0 : μ = 3.1 H 1 : μ > 3.1

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$df = n-1=75-1 =74$

The p value is:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is: 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

Step-by-step explanation:

For this case we want to test the claim that mean GPA of night students is larger than 3.1 at the .10 significance level. The claim needs to be on the alternative hypothesis so then we have the following system of hypothesis:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

We have the following info given:

$\bar X = 3.13 , s =0.03 , n =75$