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2 years ago

Writing the Equation of a Parallel Line

Mathematics

1 answer:

mario62 [17]2 years ago

4 0

Answer: math waaays can really help you

Step-by-step explanation:

math

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60 - 3d + 20 - 6 = 4d

iragen [17]

60-3d + 20-6 =4d
74-3d =4d
-3d =4d -74
-7d = -74
D=74/7

4 0

2 years ago

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Simplify (3x − 5) − (5x + 1). (2 points)

Verizon [17]

The correct answer is B. -2x-6

5 0

2 years ago

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Find the limit

Lana71 [14]

Step-by-step explanation:

<h3>Appropriate Question :-</h3>

Find the limit

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

On substituting directly x = 1, we get,

$\rm \: = \: \sf \dfrac{1-2}{1 - 1}-\dfrac{1}{1 - 3 + 2}$

$\rm \: = \sf \: \: - \infty \: - \: \infty$

which is indeterminant form.

Consider again,

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

can be rewritten as

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 3x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 2x - x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( x(x - 2) - 1(x - 2))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ {(x - 2)}^{2} - 1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 2 - 1)(x - 2 + 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)(x - 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)}{x(x - 2)}\right]$

$\rm \: = \: \sf \: \dfrac{1 - 3}{1 \times (1 - 2)}$

$\rm \: = \: \sf \: \dfrac{ - 2}{ - 1}$

$\rm \: = \: \sf \boxed{2}$

Hence,

$\rm\implies \:\boxed{ \rm{ \:\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right] = 2 \: }}$

$\rule{190pt}{2pt}$

7 0

2 years ago

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Two angles are complementary. One angle is labeled 2p+6°. The other angles is labeled 4p°. Find the value of p.

makkiz [27]

Answer:

Value of p is 14

Step-by-step explanation:

$given \: complementary \: angles \: add \: up \: to \: 90 \: degrees \\ then \\ 2p + 6 + 4p = 90 \\ 6p + 6 = 90 \\ 6(p + 1) = 90 \\ p + 1 = \frac{90}{6} \\ p + 1 = 15 \\ p = 15 - 1 \\ p = 14$

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

5 0

2 years ago

Sld;fn;sdlfhs;lfnskfhssf

Irina-Kira [14]

<h2>PLEASE MARK BRAINLIEST!</h2>

Answer:

The best answer is 12.4 units.

Step-by-step explanation:

This is because, when I totaled all of the side lengths, I got an estimated result of 12 units. 12.4 is the next closest answer, so your answer is 12.4

I hope this helps!

- sincerelynini

6 0

2 years ago

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